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3 years ago

What number is 256 compatible to

Mathematics

1 answer:

RUDIKE [14]3 years ago

5 0

The answer is the same answer 256

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WILL GIVE BRAINLIEST, RATING, AND THANKS! (There are two questions)

jekas [21]

Hi!

So we all know diameter is the width across the circle and radius is half of the diameter.

So since we know what diameter is, that would make #1) AC or the second option

For number two in case you don't know, angles 6 and 7 are vertical angles. Which, are CONGRUENT! YAY! That always makes it so easy! So if angle 6 is 30°, angle 7 will be, YES!! 30°! So easy!

So the answer to #2) 30°, or 4th option!

Hope I helped!

4 0

3 years ago

Read 2 more answers

Smplify the radical expression. How many different ways can you write your answer?

mel-nik [20]

Answer:

$2xy\sqrt[3]{2x^2z}$ and $2xy(2x^2z)^{\frac{1}{3}}$ .

Step-by-step explanation:

The given radical expression is

$\sqrt[3]{16x^5y^3z}$

We have to simplify the above expression.

The above expression can be written as

$\sqrt[3]{(2\times 8)(x^{3+2})y^3z}$

$\sqrt[3]{(2\times 2^3)(x^3\times x^2)y^3z}$ $[\because a^{m+n}=a^ma^n]$

$\sqrt[3]{(2^3x^3y^3)(2x^2z)}$

$\sqrt[3]{(2xy)^3}\sqrt[3]{2x^2z}$ $[\because (ab)^m=a^mb^m]$

$2xy\sqrt[3]{2x^2z}$ $[\because \sqrt[n]{x^n}=x]$

It can be written as exponent form.

$2xy(2x^2z)^{\frac{1}{3}}$ $[\because \sqrt[n]{a}=a^{\frac{1}{n}}]$

Therefore, the required expressions are $2xy\sqrt[3]{2x^2z}$ and $2xy(2x^2z)^{\frac{1}{3}}$ .

5 0

3 years ago

How do i graph y=1/2Sinø/2?

podryga [215]

$\fb \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}
\end{array}
\\\\
-------------------$

$\bf \bullet \textit{ stretches or shrinks}\\
\left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}$

$\bf \bullet \textit{function period or frequency}\\
\left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)$

now, with that template in mind,

$\bf \stackrel{parent~function}{y=sin(\theta )}\qquad \qquad y=\stackrel{A}{\frac{1}{2}}sin\left(\stackrel{B}{\frac{1}{2}}\theta \right)
\\\\\\
Amplitude\implies \frac{1}{2}
\\\\\\
Period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{1}{2}}\implies 4\pi$

which is pretty much the same sin(θ) function, but squished by 1/2 and elongated up to 4π, check the picture below.

7 0

3 years ago

8 1/2 x 4/11 please solve

irakobra [83]

Answer:

3 1/11

Step-by-step explanation:

8 1/2 x 4/11

Change to an improper fraction

(2*8+1)/2 * 4/11

17/2 * 4/11

68 /22

Divide the top and bottom by 2

34/11

Change back to a mixed number

11 goes into 34 3 times with 1 left over

3 1/11

7 0

3 years ago

Read 2 more answers

Please solve (show your work) n - 5 + 3n ≠ 2n - 4

FromTheMoon [43]

Answer:

23.167168n−9

simplify

n-5+(3n/n(2.718282^2))(n)-4=23.167168n2−9n=23.167168n−9

3 0

2 years ago