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GuDViN [60]
3 years ago
6

How do i graph y=1/2Sinø/2?

Mathematics
1 answer:
podryga [215]3 years ago
7 0
\fb \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}
\end{array}
\\\\
-------------------

\bf \bullet \textit{ stretches or shrinks}\\
\left. \qquad   \right. \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right. \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}

\bf \bullet \textit{function period or frequency}\\
\left. \qquad  \right. \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad  \right. \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)

now, with that template in mind,

\bf \stackrel{parent~function}{y=sin(\theta )}\qquad \qquad y=\stackrel{A}{\frac{1}{2}}sin\left(\stackrel{B}{\frac{1}{2}}\theta   \right)
\\\\\\
Amplitude\implies \frac{1}{2}
\\\\\\
Period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{1}{2}}\implies 4\pi

which is pretty much the same sin(θ) function, but squished by 1/2 and elongated up to 4π, check the picture below.


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Melons cost $20 pet Crate, and apples cost $8 per create. an order comes in for a total of 48 crates for $420. what was the numb
Alika [10]

Answer:

The number of melon was 3 and the number of apples was 45.

Step-by-step explanation:

1. Melons cost $20 per crate and apples cost $8 per create. If the total was 48 crates for $420, you can make the following system of equations, where x is the number of melons and y is the number of apples:

\left \{ {{x+y=48} \atop {20x+8y=420}} \right.

2. By applying the Method of substitution, you can solve for y in the first equation and substitute it into the second one to find x. Then, you can substitute the value of x into the first equation to find y:

y=48-x

20x+8(48-x)=420\\20x+384-8x=420\\12x=36\\x=3

3+y=48\\y=45


4 0
4 years ago
3 folders cost $2.91.<br> Which equation would help determine the cost of 2 folders?
-Dominant- [34]

Answer:

194

Step-by-step explanation:

2/3X=291

x=194

8 0
3 years ago
What is the circumference of a circle with a radius of 56 ?
kvasek [131]
<span>circumference =2(pi)r=(pi)d
use this formula. 
2*(pi)*56=351.85</span>
5 0
3 years ago
Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets
EleoNora [17]

Complete Question

Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets. Could they take 9 children and 4 adults to both shows? Show your work. A yes or no answer is not sufficient for credit.

Answer:

Yes it is  possible to take the  9 children and 4 adults to both shows

Step-by-step explanation:

From the question we are told that

    The  cost of the Matinee tickets for a child is  z =  $4

    The  cost of the Matinee tickets for an adult is  a  = $ 4

     The cost of the Evening tickets for  a child is  k =  $6

      The cost of the Evening tickets for an adult is  b =  $8    

      The  maximum amount to be spent on Matinee tickets is  m = $80

       The maximum amount to be spent on Evening tickets is  e =  $100

       The  number of child to be taken to the movies is  n  = 9

        The number of adults to be taken to the movies is  j  =  4

Now the total amount of money that would be spent on Matinee tickets is  mathematically evaluated as      

           t = 4 n + 4 j

substituting values

           t = 4 *  9  + 4* 4

           t =  52

Now the total amount of money that would be spent on  Evening ticket is mathematically evaluated as      

      T =  6n + 8j

substituting values

     T =  6(9) + 8(4)

    T = 86

This implies that it is possible to take 9 children and 4 adults to both shows

given that

      t \le m

i.e  $56  \le$ 80

and  

      T \le e

i.e   $ 86 \le $ 100

4 0
3 years ago
Dominic's water jug holds 1.25 quarts. Terrell says he can find the capacity of the jug in fluid ounces by dividing 1.25 by 32.
IceJOKER [234]
No.  Terrell is not correct.  Terrell is incorrect.  The method he offers is
inappropriate, inapplicable, and lacks veracity, and as a mathematician,
Terrell himself is devoid of integrity.  If his method is implemented, it
cannot accurately compute the capacity of Dominic's water jug in fluid
ounces.  It will produce a number that is inaccurate, fallacious, mistaken,
erroneous, and incorrect.  Moreover, the solution will be wrong.

If the units are carried through with the calculation ... as always they must ...
then it will immediately become clear that Terrell's method has produced a
solution with units of  "square quarts per ounce", whereupon any witnesses
should justifiably become nauseous.  Terrell's method should be disdained,
rejected, discarded and ignored.

==> 1.25 should not be "divided" by 32. 

==> Instead, 1.25 should be multiplied by 32.

The modified method will produce a result with units of "fluid ounces" ...
the first indication to the assembled multitude that whatever the number
is, there is a reasonable chance that it could be a correct one.

3 0
3 years ago
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