Answer:
{f, a}
Step-by-step explanation:
Given the sets:
X = {d, c, f, a}
Y = {d, e, c}
Z ={e, c, b, f, g}
U = {a, b, c, d, e, f, g}
To obtain the set X n (X - Y)
We first obtain :
(X - Y) :
The elements in X that are not in Y
(X - Y) = {f, a}
X n (X - Y) :
X = {d, c, f, a} intersection
(X - Y) = {f, a}
X n (X - Y) = elements in X and (X - Y)
X n (X - Y) = {f, a}
Answer:
Ebony need to compare ∠EFG and ∠ONM
Step-by-step explanation:
we know that
If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent by ASA
In this problem
EF ≅ ON ----> the included side
To prove congruence by ASA, of triangles EFG and ONM, the corresponding angles of the included side must be congruent
The corresponding angles of the included side are
∠MON and ∠GEF
and
∠EFG and ∠CNM
so
∠MON ≅ ∠GEF ----> given problem
and
∠EFG ≅ ∠CNM
therefore
Ebony need to compare ∠EFG and ∠ONM
Both angles must be congruent, to prove that triangles EFG and ONM are congruent by ASA
umm....... I think it was exactly 2 head
Answer:
Step-by-step explanation:
C11 = (1×1) + (-1×3) = 1-3 = -2
C12 = (1×2) + (-1×4) = 2-4 = -2
C21 = (2×1) + (1×3) = 2+3 = 5
C22 = (2×2) + (1×4) = 4+4 = 8
The product is going to be 65.34. hope that helped
