Or D 51 I really need help on this

Mathematics

2 answers:

mote1985 [20]3 years ago

8 0

Answer:

50.75

Step-by-step explanation:

You would do Pythagorean Theorem $a^{2}$ + $b^{2}[/tex=[tex]c^{2}$

but you already have C so you have to find B

Zepler [3.9K]3 years ago

4 0

Answer:

The answer is 51.

K^2+ K ^2 = H^2

32^2+ K^2= 62^2

1024+ K^2 = 3600

1024 +K^2-1024= 3600-1024

K^2 = 2576

2576 square root= 50,754

so it is 51

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Calculate the distance between each given pair of points. Round your answer to the nearest tenth, if necessary.

Ksju [112]

The answer is 5

Here are the steps:

First off, we will be using the distance formula of
$d=\sqrt{(x_ {2}- x_{2}) ^{2}+( y_{2}- y_{1})^2 }$

So we have the ordered pairs of (3,1) and (6,5)

Once you plug them into the formula it should look like this:
$d= \sqrt{(6-3)^2+(5-1)^2}$

Now we do the math inside the parenthesis and end up with:
$d=\sqrt{3^2+4^2}$

Then you multiply by the power and simplify to get:
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And the $\sqrt{25}$ =5

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3 years ago

Please help!!! If the first 4 terms of a geometric sequence are...

tigry1 [53]

Answer:

c.) aₙ = 5 × 4ⁿ⁻¹

Explanation:

Geometric sequence: aₙ = a(r)ⁿ⁻¹

where 'a' resembles first term of a sequence, 'r' is the common difference.

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