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rewona [7]
3 years ago
11

One of the implications of price elasticity of technology products is that:

Computers and Technology
1 answer:
Stels [109]3 years ago
8 0

Answer:

 The main implication of the price elasticity in the various technology products may lead increase the productivity of the products as customers buy more products due to the cheaper price of the product.

as die to the time lower costs will prompt higher deals volumes, which may compensate for the lower overall revenue. Now and again, raising the cost of your item or administration will prompt higher overall revenues yet will bring down your business volumes.

It also offer many advantages like high reliability, security and the scalability.

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ivann1987 [24]

Answer:

computer works on electricity

Explanation:

6 0
3 years ago
What is the correct name for the words Home, Insert, Design, Layout, References, etc. in the ribbon in Word 2016?
larisa86 [58]

Answer:

tabs

Explanation:

Microsoft Word refers to a word processing software application or program developed by Microsoft Inc. to enable its users to type, format and save text-based documents.

The commands which are used in Microsoft Word 2016 are displayed using series of icons that are stored on different tabs.

A ribbon is a combination of icons and tabs. In Microsoft Word 2016, the correct name for the words Home, Insert, Design, Layout, References, View, Mailings, and Review in the ribbon is tabs.

Tabs are a section of the Microsoft Word application that avails end users the opportunity to perform certain tasks such as formatting a text, changing the layout, clipboard, paragraph, styles, tables, page setup, inserting a theme, applying color, editing and inputting footnotes, header, citation and bibliography, etc.

8 0
3 years ago
Using refracted laser light to store data on a photoreceptive substrate is essentially how ___ storage works. Theoretically this
Alina [70]

Answer:

I try to search the answer but I couldn't find it

4 0
4 years ago
The insertion sort algorithm sorts using what technique?
QveST [7]

Answer:

Iteration

Explanation:

The insertion sort is based on repetition of comparing one data array (or element in a list) with the others at its left to reorganize it, normally following a size criteria (from small to big or the other way around).

At each iteration, the algorithm takes one element and compares it one by one to the others until it fit the specified criteria. Later on, it creates a space, moving the other elements, to insert it. Later, it  goes to the next element and the iteration repeats all the way through. It has some advantages over other sorting algorithms because it is easy to deploy and program it in many different languages, but at the same time it can be terribly slow when sorting large amount of data.

7 0
3 years ago
Create a structure representing a student. The member variables should include student name, student ID, and four test grades fo
Neporo4naja [7]

Answer:

Output:

Name: Brainly

ID:0001

Write the 4 tests grades of the student separated by space :10 9 8 10

Brainly

0001

10 9 8 10

Average :9.66667

'1' to continue '0' to exit :

Explanation:

#include<iostream>

#include<string>

using namespace std;

//variables declaration

struct Student {

  string id; //string declaration ID

  string name; // string declaration name

  int grades[4]; //array of 4 because it is 4 grades

};

//definition of the function get information

void inputData(Student &s){

 

   

   cout << "Name:" ;

   getline(cin,s.name);

   cout << "ID:";

   cin >> s.id;

   cout << "Write the 4 tests grades of the student separated by space :";

   for (int i = 0; i<4; i++)

       cin >> s.grades[i];

}

//definition of the function of average

double inputAvg(Student s){

   double summation;

   int temporary;

   double average;

   for (int i = 0; i<4; i++){  

      for (int j = i; j<4; j++){

         if (s.grades[j] > s.grades[i]){

             temporary = s.grades[i];

             s.grades[i] = s.grades[j];

             s.grades[j] = temporary;

         }

      }

    }

    summation = 0;

    for (int i = 0; i<3; i++){

        summation = summation + s.grades[i];  

    }

    average = summation/3;

    return average;

}

void disp(Student *s){

   cout << s->name << endl;

   cout << s->id << endl;

   for (int i = 0; i<4; i++)

       cout << s->grades[i] << " ";

   cout << endl;

   cout << "Average :" << inputAvg(*s) << endl;

   

}

int main(){

  Student st;

  int ch;

  while(true){

      inputData(st);

      disp(&st);

      cout << " '1' to continue '0' to exit :";

      cin >> ch;

      if (ch == 0)

         break;      

  }

  return 0;

}

6 0
3 years ago
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