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3 years ago

What is information technology

Computers and Technology

1 answer:

GalinKa [24]3 years ago

8 0

Answer:

nformation technology is the use of computers to store, retrieve, transmit, and manipulate data or information. IT is typically used within the context of business operations as opposed to personal or entertainment technologies. IT is considered to be a subset of information and communications technology

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A user reports that he can't connect to a specific website. you go to the user's computer and reproduce the problem. what should

Inessa05 [86]

I would check that DNS is working, and then check that the returned address accepts connections properly.

3 0

3 years ago

What is a text based language that can be used to build all kinds of things ????

Makovka662 [10]

Answer:

It's easier to define text-based programming languages. These are languages that are typed using a keyboard and stored as text files. A graphical or visual language typically uses drag and drop rather than typing. It may use icons or textual labels on blocks or elements.

4 0

3 years ago

Design a class called NumDays. The class’s purpose is to store a value that represents a number of work hours and convert it to

stepladder [879]

Answer:

See explaination

Explanation:

#include <iostream>

using namespace std;

class NumDays{

int hours;

float day;

public:

NumDays()

{

hours=0;

day=0.0;

};

NumDays(int h)

{

hours=h;

day=float(h/8.0);

};

int getHour()

{

return hours;

}

float getDay()

{

return day;

}

NumDays operator +(NumDays obj)

{

int h=getHour()+obj.getHour();

NumDays temp(h);

return temp;

}

NumDays operator -(NumDays obj)

{

int h=getHour()-obj.getHour();

NumDays temp(h);

return temp;

}

const NumDays& operator++() //prefix

{

++hours;

day=float(hours/8.0);

return *this;

}

const NumDays& operator--() //prefix

{

--hours;

day=float(hours/8.0);

return *this;

}

const NumDays operator++(int) //postfix

{

NumDays temp(*this);

++hours;

day=float(hours/8.0);

return temp;

}

const NumDays operator--(int) //postfix

{

NumDays temp(*this);

--hours;

day=float(hours/8.0);

return temp;

}

};

int main()

{

NumDays obj(2),obj2(10),obj3,obj4;

obj3=obj2-obj;

cout<<"'obj3=obj2-obj'=> Day:"<<obj3.getDay()<<"##Hour:"<<obj3.getHour()<<"\n";

obj3=obj+obj2;

cout<<"'obj3=obj+obj2'=> Day:"<<obj3.getDay()<<"##Hour:"<<obj3.getHour()<<"\n";

obj4=obj3++;

cout<<"'obj4=obj3++' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=++obj3;

cout<<"'obj4=++obj3' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=obj3--;

cout<<"'obj4=obj3--' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=--obj3;

cout<<"'obj4=--obj3' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

};

3 0

3 years ago

Tikenya was responsible for creating the PowerPoint presentation for the group project. When it was complete, she wanted to emai

Anna35 [415]

Answer:

They had to unzip or extract the zipped/ compressed presentation to see it.

Explanation:

Compressed file or a zip file contains a large file or more than one files that are packed or enclosed that large file or several files into a file or a folder.
The compressed file or folder takes less space than the actual large file or set of files.
Just as in this scenario the presentation file was larger than the size of what an email file should be. So Tikenya had to compress the file in order to email it to other members.
The other members can open the PowerPoint presentation by following any of the below mentioned methods:
In Windows to open a compressed file, right click on that file and select Extract All option.
File can also be seen by opening that file or folder and dragging that file or folder from the zipped folder to a new location. In Windows this will automatically extract the files.
This file can also be opened using a software like WinZip. Download WinZip. Then download the file which is sent in email and double click on that file which will open WinZip wizard dialogue box. Clicking that presentation file from the dialogue box will open another dialogue box confirming the opening of that file. By clicking on OK the presentation file will be opened and can be viewed now.

8 0

3 years ago

Read 2 more answers

Reference variables allow arguments to be passed by ____________.

son4ous [18]

Answer:

Reference

Explanation:

The Reference type variable is such type of variable in C# that holds the reference of memory address instead of value. Examples for reference type are classes, interfaces, delegates and arrays.

We can pass parameters to the method by reference using <em>ref </em>keyword

It’s mandatory to initialize the variable value before we pass it as an argument to the method in c#

For example,

int x = 10; // Variable need to be initialized

Add(ref x); // method call

If you pass parameters by reference in method definition, any changes made to it affect the other variable in method call.

Here's a sample program:

using System;

namespace ConsoleApplication

{

public class Test

{

public static void Main()

{

int i = 10;

Console.WriteLine("i=" + i);

Add(ref i);

Console.WriteLine("i=" + i);

Console.ReadLine();

}

public static void Add( ref int j)

{

j = j + 10;

Console.WriteLine("j="+j);

}

Output:

i=10

j=20

i=20

7 0

3 years ago