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mixas84 [53]
3 years ago
7

Find the prime factorization of 30

Mathematics
2 answers:
Aneli [31]3 years ago
6 0

30 can be written as

3 x 10

3 cannot be broken down any further

10 can be written as

5 x 2

5 and 2 cannot be broken down any further

so the prime factorization will be

3 x 5 x 2

hope this helps

sattari [20]3 years ago
5 0

Let us start dividing 30 by small prime numbers in increasing order .

the smallest prime number we use is 2

Let's divide 30 by 2 quotient is 15

so we get : 30 = 2* 15

15 is not a prime number , it can be factorized further .

now we start dividing 15

2 can not divide 15 so we move to next prime number that is 3

can 3 divide 15? yes .

we get a quotient 5

so 30 is now : 2* 15 = 2* 3*5

now we have to work on 5 but 5 is a prime number so we stop here .

the prime factorization of 30 is : 2* 3* 5

Answer : 2 *3*5

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9f + 10f - 12f I need help fam
mixer [17]

Since these are all like terms, you're essentially just adding and subtracting here.

9f + 10f -12f

Add 9f and 10f.

9f + 10f = 19f

Then, subtract.

19f - 12f = 7f

Your answer is 7f.

6 0
4 years ago
Read 2 more answers
Please answer with work!
Arlecino [84]
4 is a solution to the equation. It is true.

3 0
3 years ago
I can't figure this out. ​
Leviafan [203]

Answer:

$ 9.5

Step-by-step explanation:

total money is $20

on lunch = 1/8 × 20 = 5/2 = $2.5

on movies = 2/5 × 20 = $8

total spent = 2.5+8 =$ 10.5

left money = 20-10.5 = $ 9.5

7 0
3 years ago
Which expression is equivalent to 4 (9 + 7)
Bad White [126]

4(9+7) = 36+28 = 64

open the parentheses, then simplify.

8 0
2 years ago
(06.03)
ruslelena [56]

Answer:

Median is best suitable, it = 4

Step-by-step explanation:

Median is best suitable as this data' measure of central tendency. As, mean is suitable in a normally distributed data. But, in skewed (uneven) distributions, where outliers exist, median is more suitable - as it is positional average, not effected by extreme values ie outliers.

Median :

Ascending order : 0 , 1 , 2 , 2 , 4 , 4 , 4 , 5 , 5

Number (N) = 9. So, median = (N+1/ 2)th observation

= { (9 +1) / 2 } th = (10 / 2)th = 5th observation = 4

8 0
3 years ago
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