All categories

3 years ago

A circle has a circumference of 11{,}30411,30411, comma, 304 units. What is the diameter of the circle?

Mathematics

1 answer:

tigry1 [53]3 years ago

8 0

Answer:

The diameter of the circle is $3,600\ units$

Step-by-step explanation:

we know that

The circumference of a circle is equal to

$C=\pi D$

where

D is the diameter

In this problem we have

$C=11,304\ units$

assume $\pi=3.14$

substitute the values and solve for D

$11,304=(3.14)D$

$D=11,304/(3.14)=3,600\ units$

You might be interested in

The graph shows the relationship between the number of apples and their cost. For the point (1, r), what is the value of r?

3241004551 [841]

Answer:

Step-by-step explanation:

When you check the point that is on X, it is a little over halfway to the point 1,2. It would be like 1,1.5 or 1,1.6.

5/3 is the equivalent to 1.6 so that answer would make the most sense.

4 0

3 years ago

Read 2 more answers

If < A and < B are a linear pair, and < A = 68 °, then < B = _____.

Contact [7]

Answer:

Option b, 112°

Step-by-step explanation:

<A+<B=180

or, 68+<B=180

or, <B=112

Answered by GAUTHMATH

5 0

3 years ago

Need help with this question!!

alexira [117]

Answer:

is number 2

Step-by-step explanation:

3 0

4 years ago

Due this Thursday.. help pls.

kobusy [5.1K]

2004 was a leap year so 29/366=7.9%

4 0

3 years ago

Dont leave any links please

Olin [163]

Answer:

m^2/n

Step-by-step explanation:

The following laws of exponent are useful to this problem:

$\displaystyle \large{ {(mn)}^{b} = {m}^{b} {n}^{b} } \\ \displaystyle \large{ {n}^{ - b} = \frac{1}{ {n}^{b} } }$

We are given the expression:

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } }$

Use the first law of exponent above.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{(8)( \frac{1}{4}) } {n}^{ ( - 4)( \frac{1}{4}) } } \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } {n}^{ - 1} }$

Make sure to recall the important necesscary fundamental math such as operation with negative numbers/integers, basic division, fraction, etc.

From the expression, apply the second law of exponent to n^-1.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n}^{1} } )} \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n} } )} \\$

Multiply m in.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = \frac{ {m}^{2} }{ {n} } }$

Thus the answer is m^2/n.

6 0

3 years ago