In equation, let x be the number of male students
a be the number of adults
y be the number of female students.
x= 7a+1
a= x/7 -1
y= x/2 or (7a + 1)/ 2
a + b = 82, let b be the number of students.
a + (x + y) = 82
a + [7a+1 + (7a+1)/2] = 82
a + [{2(7a+1) + 7a+1} / 2] = 82
a + [(14a +2 + 7a +1) / 2] = 82
a + [(21a + 3) / 2] = 82
(2a+ 21a + 3) / 2 = 82
(23a + 3) / 2 = 82
23a + 3 = 164
23a = 164 -3
23a = 161
a = 7
x = 7(7) +1, 49+1 = 50 male students
y=x/2, 50/2, 25 female students
50(male students) + 25(female students) + 7 (adults) = 82
Answer:
s = 14m + 458
Step-by-step explanation:
current amount = 458
14 per month
s = 14m + 458
Answer:
x = 5/2
Step-by-step explanation:
4x - 1/2 = x +7
4x - 1/2 - x = 7
4x - x = 7 + 1/2
3 x = 15/2
x = 5/2
Answer from Gauthmath
Answer:
A.
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B. Yes, Pablo can buy 2 pair of pants and 4 shirts.
Step-by-step explanation:
A. Let x be the number of pairs of pants and y be the number of shirts.
We have been given that Pablo wants to purchase 6 additional clothing pieces for his wardrobe. We can represent this information as:
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We are also told that each pair of pants costs $20 and each shirt costs $15. So the cost of x pairs of pants will be 20x and cost of y shirts will be 15y.
As Pablo wants to spend $100 on clothing, so we can represent this information as:
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Therefore, the system of equation representing the given situation will be:
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B. To find if Pablo can buy 2 pair of pants and 4 shirts we will substitute x=2 and y=4 in our both equations.
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We can see that x=2 and y=4 satisfies our both equation, therefore, Pablo can buy 2 pair of pants and 4 shirts.
Answer:
C. <em>3,300</em>
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Step-by-step explanation: