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Serga [27]
3 years ago
13

Due this Thursday.. help pls.​

Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0
2004 was a leap year so 29/366=7.9%
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Which is not personally liable for any losses or damages?
cupoosta [38]

Answer:


Step-by-step explanation:

Ur answer should be C

5 0
3 years ago
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PLEASE HELP I REALLY NEED IT RN
Crank

Answer:

Claim: Basically Carlos is saying that every number and its opposite are on the positive and negative side of the number.

Which number supports tht claim and which number refutes(disagree) with that claim?

Step-by-step explanation:

The opposite of -24 is 24, located on the positive side of the number line

The opposite of 605 is -605, located on the nagative side of the number line.

The opposite of 0 is 0.

8 0
3 years ago
(5x^2+20x) ÷(x+4) divide, it's really important, I thank you for the people who help me in this :)
Sergio [31]

Answer:

5x

Step-by-step explanation:

Given expression: \frac{5x^2+20x}{x+4}

Take the common number 5 outside in the numerator.

\frac{5x^2+20x}{x+4}=\frac{5(x^2+4x)}{x+4}

Now, take x common in both the terms in numerator.

\frac{5(x^2+4x)}{x+4}=\frac{5x(x+4)}{x+4}

Cancel out the common factor in the both numerator and denominator.

\frac{5x(x+4)}{x+4}=5x

Hence, the answer is 5x.

3 0
4 years ago
Can someone please help and explain its due in a littleee
jek_recluse [69]

f(x) =  {x}^{2}  - 3x + 2

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (-1)

f( - 1) =  {( - 1)}^{2}  - 3 \times ( - 1) + 2  \\  \\   1  + 3 + 2  \\  \\   6.

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (z)

f(z) =  {z}^{2}  - 3 \times z + 2  \\  \\  {z}^{2}  - 3z + 2  \\  \\  {z}^{2} - 2z - z + 2 \\  \\ z(z - 2) - 1(z - 2) \\  \\ (z - 1)( z -2 ) \\  \\ (z - 1) = 0  \:  \: , \:  \: (z - 2) = 0\\  \\ z =  1 \:,  \: 2

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (x+1)

f(x + 1)  = {x}^{2}  -  3x + 2 \\  \\  {(x + 1)}^{2}  - 3 (x + 1) + 2 \\  \\  {x}^{2}  + 1 + 2x - 3x - 3 + 2 \\  \\  {x}^{2}  - x \\  \\ x(x - 1) \\  \\ x(x - 1) = 0   \\  \\  x - 1 =  \frac{0}{x}  \\  \\ x - 1 = 0 \\  \\ x = 1.

<h2>•••••••••••••••••••••••••••••••••</h2>

put x = (√2 + 1 )

f( \sqrt{2}  + 1) =  {x}^{2}  - 3x + 2 \\  \\  {( \sqrt{2} + 1) }^{2}  - 3( \sqrt{2}  + 1) + 2 \\  \\ 2 + 1 +  2\sqrt{2}  - 3 \sqrt{2}  - 3 + 2 \\  \\ 3 - 1 \sqrt{2}  - 1 \\  \\ 2 -  \sqrt{2}  \\   \\  2 - 1.4 (optional \:  \:  \: steps)\\  \\ 0.6 \:  \:

4 0
2 years ago
Consumers’ willingness to pay depends on what income and prices of related goods.
kolezko [41]
Based on the given description above, the answer for this would be the term DEMAND. Demand is defined as the consumers' <span>willingness to pay depends on what income and prices of related goods. Hope this is the answer that you are looking for. Have a great day ahead!</span>
4 0
4 years ago
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