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Brrunno [24]
3 years ago
13

An equation is shown below: 3 e - 8 ) = 5 e + 43 Solve this equation showing at least 4 steps and explain each step.

Mathematics
2 answers:
Sedbober [7]3 years ago
8 0

Answer:

-25 1/2 =e

Step-by-step explanation:

3 e - 8  = 5 e + 43

Subtract 3e from each side

3 e - 8 -3e = 5 e-3e + 43

Simplify

-8 = 2e +43

Subtract 43 from each side

-8-43 = 2e+43-43

Simplify

-51 = 2e

Divide each side by 2

-51/2 = 2e/2

Simplify

-25 1/2 =e

Mariana [72]3 years ago
3 0

Steps to solve:

3e - 8 = 5e + 43

~Add 8 to both sides

3e - 8 + 8 = 5e + 43 + 8

~Simplify

3e = 5e + 51

~Subtract 5e to both sides

3e - 5e = 5e - 5e + 51

~Simplify

-2e = 51

~Divide -2 to both sides

-2e/-2 = 51/-2

~Simplify

e = -25 1/2

Best of Luck!

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Geometry// Find the measure of arc CD. Please explain ! Brainliest given!
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Answer:

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In the New York State number lottery, you pay $1 and pick a number from 000-999. If your number comes up, you win $500, which is
slava [35]

Answer:

Expected value of profit is ≅ $15.80

Step-by-step explanation:

from the Question,

Let the variable X represents the expected value of profit. X is called as random variable because picking a number from 000-999 digits is a Random process.

P(win) = 0.001

So, P(lose) = 1-0.001=0.999

Suppose that,

we really want to win this lottery. so we can go to the store and spend $1000 to buy all ticket (from 000 - 999). This would ensure your winning of $500 with one of the tickets (for a $499 profit), but the other 999 would be  losers (for a $999 loss).

What would be your average winnings on a per-ticket basis?

               u = E(x) =∑x\times P(x)

                  = 499\times0.0001+ (-1)\times0.999

                  = -0.50

Here,

Standard deviation of the expected winnings

           V (X) =  ∑(x-u)^{2} \times P(x)

                     =   ∑ (499-(-0.50))^{2} \times 0.001 + (-1-(-0.50))^{2} \times 0.999

                     = 249.75

Taking square root of the variance to get the standard deviation:

               SD(x) = \sqrt{249.75}

                        ≅ $15.80

Hence

The expected value of profit is ≅ $15.80

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