Please help me. i am having a bit of trouble.
2 answers:
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Answer:
Given:-
The length of copper wire (L) = 270 cm
Area of cross-sectional (A) = 0.030
and specific resistance (ρ) = ohm-cm.
Use the formula R=(Specific resistance*L)/A, to calculate the Resistance(R)
then, ohm
Simplify:
R = 0.0162 ohm = ohm
Therefore, the resistance of copper wire is, Ω
Answer:
x = 13
Step-by-step explanation:
Find the diagram attached
From the diagram, the sum of angle of the straight line BCD is 180°. Hence;
<BCE+<ECF<90 = 180
<BCE+64+90=180
<BCE+154 = 180
<BCE = 180-154
<BCE = 26°
Next is to get x.
The sum of interior angles <BCE and <BEC is equal to exterior angle <ABE
<BCE + <BEC = <ABE
26+x = 3x
Collect like terms
26 =3x-x
26=2x
x = 26/2
x = 13
Hence the value of x is 13
