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Ira Lisetskai [31]
4 years ago
5

Need answers for Question 5 and 6

Mathematics
1 answer:
dexar [7]4 years ago
4 0

Answer:

5. A  6. B

Step-by-step explanation:

5. there are 4 letters out of 12 cards, so the probability is 4/12, which equals 1/3

6. there are two J cards out of 12 cards, so the probability is 2/12. which equals 1/6

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Which of the following numbers has the correct number of significant digits for the sum of 4.0125 and 5.72?
sladkih [1.3K]

Answer:

the answer to your question is 9.73

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2 years ago
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Point w (-6,7) is rotated 90 clockwise where is w what is the answer
Orlov [11]
(6,7) should be the answer
8 0
3 years ago
What is “Twice a number is more than the sum of that number and 9” written in equation form?
icang [17]
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5 0
4 years ago
What is the lcm of 6and15
suter [353]
<h3>Answer:  30</h3>

========================================

Explanation:

Method 1)

The short way to find this answer is to multiply the values together to get 6*15 = 90, then divide by the GCF 3 getting 90/3 = 30 as the LCM.

-------------

Method 2)

The longer way is to list the prime factorizations of each value

6 = 2*3

15 = 3*5

The unique factors are: 2, 3, 5

The most that each unique factor happens is one time.

Those unique factors multiply out to 2*3*5 = 30

---------------

Method 3)

Another way is to list out the multiples of 6 and 15

multiples of 6 = {6, 12, 18, 24, 30, 36, 42, 48, ...}

multiples of 15 = {15, 30, 45, 60, 75, 90, 105, ...}

We see that 30 is the smallest value in both sets, so 30 is the LCM.

8 0
4 years ago
A gumball machine has different flavors sour apple,grape,orange and cherry . There are six of each flavor. $.50 are put in the m
tamaranim1 [39]

Answer:

30/552

Step-by-step explanation:

In order to solve this problem you need to multiply the probability of getting grape for the first gumball with the probability of getting grape for the second gumball. Since there are 6 grape gumballs and a total of 24 gumballs (6*4). Then the probability of getting grape for the firs one is

\frac{6}{24}

Now there are only 5 grape gumballs available and one less in the total supply, therefore the probability of getting grape in the second try is

\frac{5}{23}

Finally we multiply them together to find the probability of getting two grapes in a row.

\frac{6*5}{24*23} = \frac{30}{552}

4 0
3 years ago
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