Answer:
Step-by-step explanation:
2x^2-6x+10=0
2(x^2-3x)+10=0
2(x-(3/2))^2-9/4)+10=0
2(x-(3/2))^2+10-9/2=0
2(x-(3/2))^2+(20-9)/2=0
2(x-(3/2))^2+11/2=0
2(x-(3/2))^2=-11/2
square is always positive so there is no solution
4.16
50/12
1st Option
Hope it helps
Number 15 is no solution.
Number 27 is that x has to be between -2 or 2.
This could be explained as -2≤x≤2
