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Karolina [17]
3 years ago
6

A 5.0 g of copper was heated from 20°C to 80°C. How much energy was used to heat Cu? The specific heat of copper is 0.385 J/gC.

Chemistry
1 answer:
aleksklad [387]3 years ago
7 0

Answer: a. 115.5 J.

Explanation:

Q=mc\Delta T

where,

Q = heat absorbed = ?

m = Mass of copper = 5.0 g

c = specific heat capacity of copper= 0.385 J/g.°C

\Delta T = change in temperature = T_2-T_1=(80^0C-20^oC)=60^0C

Putting values in above equation, we get:

Q=5.0g\times 0.385J/g.^oC\times 60^0C

Q=115.5Joules

Hence, the energy used to heat Copper is 115.5 Joules.

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5 0
3 years ago
(NEED HELP IMMEDIATELY) In a gene, which base sequence codes for two amino acids?
Leni [432]

Answer:

\boxed {\boxed {\sf 3. \ GAGCTC}}

Explanation:

Amino acids are the monomers or building blocks of protein. Proteins are created during protein synthesis according to the genetic information or DNA in an organism.

The DNA is translated to messenger RNA in the nucleus. It travels to the ribosome. There, the mRNA is "read off" in threes. <u>Three nucleotides</u> make up  a <u>codon.</u> Transfer RNA with the corresponding anticodon and an amino acid attaches to the codon and a chain of amino acid forms.

If 3 nucleotides make 1 codon which makes 1 amino acid, then we need double that or 6 nucleotides to make 2 amino acids.

The only answer choice with 6 nucleotides is <u>Choice 3: GAGCTC</u>

3 0
3 years ago
How do how do you know the number of valence electrons in an atom from the periodic table? User: How do you know the number of v
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The valence electrons is last outer shell of an atom. So it is the last number of the electron configuration on the periodic table.
4 0
3 years ago
To 100.0 g water at 25.00 ºc in a well-insulated container is added a block of aluminum initially at 100.0 ºc. the temperature o
11111nata11111 [884]
When the amount of heat gained = the amount of heat loss

so, M*C*ΔTloses = M*C* ΔT gained

when here the water is gained heat as the Ti = 25°C and Tf= 28°C so it gains more heat.

∴( M * C * ΔT )W = (M*C*ΔT) Al

when Mw is the mass of water = 100 g 

and C the specific heat capacity of water = 4.18

and ΔT the change in temperature for water= 28-25 = 3 ° C

and ΔT the change in temperature for Al = 100-28= 72°C

and M Al is the mass of Al block

C is the specific heat capacity of the block = 0.9 

so by substitution:

100 g * 4.18*3 = M Al * 0.9*72

∴ the mass of Al block is = 100 g *4.18 / 0.9*72

                                          = 19.35 g 





4 0
3 years ago
A 1.45 g sample of an iron ore is dissolved in an acid and the iron is obtained as Fe+2 (ag). To titrate the solution, 21.6 mL o
trapecia [35]

Answer:

42.3%

Explanation:

By the reaction given the stoichiometry between MnO₄⁻ and Fe⁺² is 1 mol of MnO₄⁻ to 5 moles of Fe⁺². When KMnO₄ dissolves, it forms the same amount of K⁺ and MnO₄⁻ (1:1:1), so the number of moles of MnO₄⁻ used is:

n = Volume*concentration

n = 0.0216 L * 0.102 mol/L

n = 2.20x10⁻³ mol

1 mol of MnO₄⁻ -------------------- 5 moles of Fe⁺

2.20x10⁻³ mol ---------------------- x

By a simple direct three rule

x = 0.011 mole

The molar mass of iron is 55.8 g/mol. The mass is the molar mass multiplied by the number of moles, thus:

m = 55.8*0.011

m = 0.614 g

Then, the percent of iron in the ore is:

(mass of iron/ mass of ore) *100%

(0.614/1.45)*100%

42.3%

3 0
3 years ago
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