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SCORPION-xisa [38]
3 years ago
15

I want to paint a paint a parallelogram shaped area that has a base of 12 feet and a height of 4 feet. It cost 3.90$to cover one

squat foot with paint
Mathematics
1 answer:
OleMash [197]3 years ago
4 0

It would cost you $187.20 to paint that

<em>Have a great night!</em>

<em></em>

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At which of the following points do the two equations f(x)=3x2+5 and g(x)=4x+4 intersect?
Basile [38]

Answer:

(\frac{1}{3}, \frac{16}{3} ) and (1, 8 )

Step-by-step explanation:

To find the points of intersection equate f(x) and g(x), that is

3x² + 5 = 4x + 4 ( subtract 4x + 4 from both sides )

3x² - 4x + 1 = 0 ← in standard form

(3x - 1)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

3x - 1 = 0 ⇒ 3x = 1 ⇒ x = \frac{1}{3}

x - 1 = 0 ⇒ x = 1

Substitute these values into either of the 2 functions for corresponding y- coordinates.

Substituting into g(x), then

g(1) = 4(1) + 4 = 4 + 4 = 8 ⇒ (1, 8 )

g(\frac{1}{3} ) = \frac{4}{3} + 4 = \frac{16}{3} ⇒ (\frac{1}{3}, \frac{16}{3} )

3 0
4 years ago
Are 4/7 and 12/21 equivalent fractions? Why or why not?
Anni [7]

Answer:

Yes

Step-by-step explanation:

12/21 simplified is 4/7. if you divide the numerator (12) by 3 and the denominator (21) by 3, you get 4 and 7, or 4/7 if you put it together.

5 0
3 years ago
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A piece of wire is 240 cm long.
lesya692 [45]

Answer: 3

Step-by-step explanation:

8 0
3 years ago
Use the derivative function, f ' ( x ) , to determine where the function f ( x ) = − 2 x 2 + 13 x − 8 is increasing.
prisoha [69]

Answer:

f is increasing on interval (-infty, 13/4)

Inequality notation: x<13/4

In words: f is increasing on the interval of x that is less than 13/4.

Step-by-step explanation:

f is increasing on interval of x if f' of such interval is positive.

f=-2x^2+13x-8

Differentiate both sides

(f)'=(-2x^2+13x-8)'

Sum and difference rule:

f'=(-2x^2)'+(13x)'-(8)'

Constant multiple rule:

f'=-2(x^2)'+13(x)'-(8)'

Power rule (recall x=x^1):

f'=-2(2x^1)+13(1x^0)-(8)'

Constant rule:

f'=-2(2x^1)+13(1x^0)-(0)

Recall again x^1=x:

f'=-2(2x)+13(1x^0)-(0)

Recall x^0=1:

f'=-2(2x)+13(1×1)-(0)

Associative property of multiplication:

f'=-(2×2)x+13(1×1)-(0)

Performed grouped multiplication:

f'=-(4)x+13(1)-(0)

f'=-4x+13-(0)

Additive identity:

f'=-4x+13

f' is positive when -4x+13>0.

Subtract 13 on both sides:

-4x>-13

Divide both sides by -4:

x<-13/-4

x<13/4

f is increasing on interval (-infty, 13/4)

4 0
2 years ago
Solve the following inequality: 6x-4 3<br> B.x&lt;3<br> C.x≤3<br> D. no solution
Tcecarenko [31]

Step-by-step explanation:

5 0
3 years ago
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