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Lady_Fox [76]
3 years ago
8

Find the median of the following data set. 0.32, 0.68, 1.05,0.74, 0.6, 0.91

Mathematics
2 answers:
ra1l [238]3 years ago
8 0
Set the numbers in order than start crossing them out left to right staring from the outter numbers. Then take the remaining two numbers add them and divide the new number by 2
adell [148]3 years ago
6 0
First put them in numerical order: .32, .6, .68, .74, .91, 1.05. The median is the number in the middle: .68 and .74 are both in the middle. Since there are 2 numbers in the middle we find the average of them: add them together: .68+.74=1.42. Then divide that number by 2 (the number of addens you had): 1.42/2=.71. The median is .71 :)
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Help & explain answer pls
AlekseyPX
The solution is (-2,4) she right both have the same solution because if you solve both of them you will get (-2,4)
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3 years ago
Which complex number is equivalent to the given expression (2+I)(8-3i)-(23+34i)
DENIUS [597]

Answer: -4 - 32i                  

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6 0
3 years ago
Find the dimensions of the rectangle with area 256 square inches that has minimum perimeter, and then find the minimum perimeter
mezya [45]

Answer:

Dimensions: A=a\cdot b=256

Perimiter: P=2a+2b

Minimum perimeter: [16,16]

Step-by-step explanation:

This is a problem of optimization with constraints.

We can define the rectangle with two sides of size "a" and two sides of size "b".

The area of the rectangle can be defined then as:

A=a\cdot b=256

This is the constraint.

To simplify and as we have only one constraint and two variables, we can express a in function of b as:

b=\frac{256}{a}

The function we want to optimize is the diameter.

We can express the diameter as:

P=2a+2b=2a+2*\frac{256}{a}

To optimize we can derive the function and equal to zero.

dP/da=2+2\cdot (-1)\cdot\frac{256}{a^2}=0\\\\\frac{512}{a^2}=2\\\\a=\sqrt{512/2}= \sqrt {256} =16\\\\b=256/a=256/16=16

The minimum perimiter happens when both sides are of size 16 (a square).

4 0
3 years ago
What is the slope intercept form for this graph ? Please answer !!
Dmitry_Shevchenko [17]

y =  \frac{3}{2} x + 3
5 0
3 years ago
Read 2 more answers
17. Which of the following equations would graph a line parallel to 3y = x + 5? (
Naddik [55]

The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st

Step-by-step explanation:

Parallel lines have same slopes and different y-intercepts

To find which equation would graph a line parallel to 3y = x + 5

1. Put the equation in the form of y = mx + c

2. m is the slope of the line and c is the y-intercept

3. Look for the equation which has the same values of m and different

   values of c

∵ 3y = x + 5

- Divide each term of the equation by 3 to put the equation in the

 form of y = mx + c

∴ y = \frac{1}{3} x + \frac{5}{3}

∴ m = \frac{1}{3}

∴ c = \frac{5}{3}

The first answer:

∵ 3y = x + 1

- Divide each term of the equation by 3

∴ y = \frac{1}{3} x + \frac{1}{3}

∴ m = \frac{1}{3}

∴ c = \frac{1}{3}

∵ The two equations have same slope m = \frac{1}{3}

∵ The two equations have different y-intercepts c = \frac{5}{3}

   and c = \frac{1}{3}

∴ 3y = x + 5 and 3y = x + 1 represent two parallel lines

The equation 3y = x + 1 would graph a line parallel to 3y = x + 5

Learn more:

You can learn more about slope of a line in brainly.com/question/12954015

#LearnwithBrainly

8 0
3 years ago
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