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Makovka662 [10]
3 years ago
11

You can reflect a square onto itself across ___ different lines of reflection.

Mathematics
1 answer:
notka56 [123]3 years ago
8 0
The answer is c because if you have a square and you look at a reflection you can see that a square has 4 sides so if you look at the reflection you would see another of the square. So what you would do is 4+4 which equals to 8.
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what man we can barley see

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Step-by-step explanation:

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Use the method of undetermined coefficients to find the general solution to the de y′′−3y′ 2y=ex e2x e−x
djverab [1.8K]

I'll assume the ODE is

y'' - 3y' + 2y = e^x + e^{2x} + e^{-x}

Solve the homogeneous ODE,

y'' - 3y' + 2y = 0

The characteristic equation

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For nonhomogeneous ODE (1),

y'' - 3y' + 2y = e^x

consider the ansatz particular solution

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Substituting this into (1) gives

a(x+2) e^x - 3 a (x+1) e^x + 2ax e^x = e^x \implies a = -1

For the nonhomogeneous ODE (2),

y'' - 3y' + 2y = e^{2x}

take the ansatz

y = bxe^{2x} \implies y' = b(2x+1) e^{2x} \implies y'' = b(4x+4) e^{2x}

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Lastly, for the nonhomogeneous ODE (3)

y'' - 3y' + 2y = e^{-x}

take the ansatz

y = ce^{-x} \implies y' = -ce^{-x} \implies y'' = ce^{-x}

and solve for c.

ce^{-x} + 3ce^{-x} + 2ce^{-x} = e^{-x} \implies c = \dfrac16

Then the general solution to the ODE is

\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}

6 0
1 year ago
Acellus. Solve for x. x = ?
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Answer:

according to basic proportionality theorem

\qquad\sf {:}\longrightarrow 25/35=x/63

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5 0
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UNO [17]

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Step-by-step explanation:

24 = 2x + 10

24 - 10 = 2x + 10 - 10 (Subtract 10 from both sides)

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7 = x

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8 0
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