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neonofarm [45]
2 years ago
7

What is 10 times as much as in decimal 0.2?

Mathematics
1 answer:
saul85 [17]2 years ago
3 0
0.02 this isa the answer


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An amusement park charges a $15 entrance free plus $3.25 for each ride. Part A: Write an equation that represents the situation.
IceJOKER [234]

Answer:

Look below

Step-by-step explanation:

Part A: Equation would be in the y=mx+b format. m, or the slope, would be the cost that varies depending on the number of things that happen so m=3.25. b would be the fix cost so it is 15 so the equation ends up being y=$3.25x + $15.

Part B: Initial value is 15 since it is the fix cost, and 3.25 is the rate of change since it added as the number of rides increase.

Part 3: To solve this you substitute 7 into x so y=$3.25(7) + $15 = $37.75

I hope this explains it well.

7 0
3 years ago
Which congruence theorem can be used to prove<br> ABR = RCA?
vivado [14]

Answer: The HL Theorem can be used to prove ABR ≅ RCA because both triangles share the same hypotenuse and a leg. The HL theorem states that If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.

8 0
2 years ago
9.36 as an improper fraction
Rasek [7]

Answer: 13/10

Step-by-step explanation:

6 0
3 years ago
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Dennis is cutting construction paper into rectangles for a project he needs to cut one rectangle that is 12 inches times 15 1/4
Nataly_w [17]

Answer:

Dennis need 288.91 square inches of construction paper for his project.

Step-by-step explanation:

Dennis is cutting construction paper into rectangles for a project.

He needs to cut one rectangle that is 12 inches times 15 1/4 inches

First convert the mixed fraction to improper fraction

15\frac{1}{4} = \frac{(15\times4) + 1}{4} = \frac{61}{4}

So the area of 1st rectangle is

A_1 = 12\times \frac{61}{4} = 183 \: in^{2}

He needs to cut another rectangle that is 10 1/3"" x 10 1/4""

The symbol " means inches

First convert the mixed fraction to improper fraction

10\frac{1}{3} = \frac{(10\times3) + 1}{3} = \frac{31}{3}

10\frac{1}{4} = \frac{(10\times4) + 1}{4} = \frac{41}{4}

So the area of 2nd rectangle is

A_2 = \frac{31}{3}\times \frac{41}{4} = 105.91 \: in^{2}

The total construction paper needed for this project is

A = A_1 + A_2\\\\A = 183 + 105.91\\\\A = 288.91 \: in^{2}

Therefore, Dennis need 288.91 square inches of construction paper for his project.

6 0
3 years ago
determine the mode for the following set of test scores: 63, 70, 75, 80, 85, 85, 85, 92, 92, 95, 99. (a.92) (b.85) (c.84) (d.83)
Alenkasestr [34]

The mode is the score that occurs the most

Here it is 85

Choice B

5 0
3 years ago
Read 2 more answers
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