6 peaches were there in each box
Solution:
18/3 = 8
Answer: 23.2
Step-by-step explanation:
You would start off by finding the base, which is 18*12. That equals 216 meters squared, you multiply that by 2 to get the surface area of your 2 bases. That equals 432 meters squared. To find the surface area of the sides (on the left and right side), you would use the equation length times height. To plug in the numbers, you use 12*4, that is 48 meters squared. There are 2 sides, so multiply by 2, to get 96 meters squared. To find the last side, you take length times width, plug in the numbers. Those numbers are 4*18, which equals 72 meters squared. Once again, there are two sides, so you multiply by 2, to get 144 meters squared. Next, as the final step, you add up all of the final numbers. They are: 432+96+144 which equals 672 meters squared.
Your final answer is 672 meters squared.
I hope this helps!
Answer:
d
Step-by-step explanation:
We know that diagonals bisect angles of a rhombus, meaning that they split the angles of two equal parts, that opposite angles are equal, and that the angles of a quadrilateral, such as a rhombus, add up to 360 degrees.
Looking at the drawing I uploaded, and taking into account that diagonals bisect angles of a rhombus, we can say that angle x = y and z = 5x-18
Next, given that opposite angles are equal, we can say that angle B = angle D and angle A = angle C. Therefore,
A+B+C+D= 360 (as the angles of a quadrilateral add up to 360)
A + B + A + B = 360 (plugging in A for C and B for D)
2 ( A + B) = 360
A + B = 180
x + y + z + 5x - 18 = 180 (plugging x+y in for A, and z+5x-18 in for B, as x and y make up A and z and 5x-18 make up B)
x+x+5x-18+5x-18 = 180 (because x=y and z=5x-18)
2(x+5x-18) = 180
divide both sides by 2
x+5x-18=90
6x-18=90
add 18 to both sides
6x=108
divide both sides by 6
x = 18
Answer:
Ray AC.
Step-by-step explanation:
They are the same; if you look at the figure, you can see that A and C are the same distance from each other and a ray in either direction would be equivalent to its counterpart.