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3 years ago

How many ways can we list the names Bobby, Billy, Mickey, Sally, Betty, Jimmy, Mary, and Fred?

Mathematics

1 answer:

VikaD [51]3 years ago

4 0

Answer:

so sorry

Step-by-step explanation:

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Diego and Jada are both trying to write an expression with fewer terms that is equivalent to

UkoKoshka [18]

Answer: Diego, 4a + 9b is equivalent

Step-by-step explanation:

7a + 5b - 3a + 4b

= (7a - 3a) + (5b + 4b) We rerange the variables, and put them together with (), which make it more clear to solve.

= 4a + 9b

7 0

3 years ago

Pls plsss help with math, it’s easyyy!! explanation needed!!

zimovet [89]

Answer:

C. x = -12 and x = 2

Step-by-step explanation:

-x²-10x+24=0 Original equation

x²+10x-24=0 Divide everything by -1

(x+12)(x-2)=0 Factor it out

x=-12,2 Solve so that the inside of the parentheses equals 0

7 0

3 years ago

Read 2 more answers

What is another way to say 345 centimeters?

Zolol [24]

100 centimeters is equal a meter so you can say 345 centimetres is the same as 3,45 metres

i hope i helped you somehow

7 0

3 years ago

Read 2 more answers

Which statements about the graph of the function f(x) = 2x2 – x – 6 are true? Select two options.

natka813 [3]

Answer:

D and C

Step-by-step explanation:

Took the quiz

5 0

3 years ago

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Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer

almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

$\to \mu=\frac{\sum xi}{n}$

$=22.8$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187$

In point b:

$\to \mu=\frac{\sum xi}{n}$

$=20.6875$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251$

In point c:

$\to \mu=\frac{\sum xi}{n}$

$=21$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179$

In point d:

$\to \mu=\frac{\sum xi}{n}$

$=20.8375$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\ =\sqrt{0.553166667} \\\\ =0.7438$

6 0

3 years ago