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3 years ago

Are the following fractions proportional?? .4/.8 and .71/.4

Mathematics

1 answer:

Neporo4naja [7]3 years ago

4 0

Answer:

yes they are

Step-by-step explanation:

see nobody answers correctly:)

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Write x^2 - 6x + 7= 0 in the form (x-a)^2 b, where a and b are intergers.

dimaraw [331]

Answer:

(x-3)^2=2

Step-by-step explanation:

${x}^{2} - 6x + 7 = 0 \\ adding \: 2 \: both \: sides \\ {x}^{2} - 6x + 7 + 2 = 0 + 2 \\ {x}^{2} - 6x + 9 = 2 \\ {x}^{2} - 6x + {(3)}^{2} = 2 \\ (x - 3) ^{2} = 2$

4 0

4 years ago

Reduce to lowest terms: -5/8 divided by 1/4. PLEASE HELP!!

Wewaii [24]

$- \frac{5}{8} \div \frac{1}{4} \\ \\ - \frac{5}{8} \times 4 \\ \\ - \frac{20}{8} \\ \\ - \frac{5}{2} \\ \\ Answer: \fbox {-5/2} \ or \ \fbox {-2.5}$

4 0

4 years ago

Read 2 more answers

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morpeh [17]

If we solve this equation: 8.9=logx+7.9

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5 0

3 years ago

The first three steps of completing the square to solve the quadratic equation x2 +4x-6=0

hodyreva [135]

Answer:

Step-by-step explanation:

1. Move the 6 to the other side: x^2 +4x =6

2. Square half the coefficient of the x term: (4/2)^2 = 4

3. Add this 4, and then subtract this 4, from x^2 + 4x:

x^2 +4x + 4 - 4 =6

4. Rewrite this perfect square as the square of a binomial:

(x + 2)^2 - 4 = 6

5. Add 4 to both sides: (x + 2)^2 = 10

6. Find the sqrt of both sides: x + 2 = √

8 0

4 years ago

4. k/6 = 8/16 5. 5.4/7 = 27/h 6. 8/11 = 4/y+2

kupik [55]

Answer:

4. $k=3\\$

5. $h=35$

6. $\frac{7}{2}$ or 3.5

Step-by-step explanation:

$\frac{k}{6}=\frac{8}{16}$

Multiply those 2 values whose diagonal has both terms and divide by the term whose diagonal has the variable.

$k=\frac{8*6}{16}\\ k=\frac{48}{16}\\ k=3$

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$\frac{5.4}{7}=\frac{27}{h}$

$h=\frac{7*27}{5.4} \\h=\frac{189}{5.4}\\ h=35$

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$\frac{8}{11}=\frac{4}{y+2}$

$y+2=\frac{11*4}{8}\\ y=\frac{11*4}{8}-2\\y=\frac{44}{8}-2 \\y=\frac{11}{2}-2\\ y=\frac{11-2*2}{2}\\ y=\frac{11-4}{2}\\ y=\frac{7}{2}=3.5$

7 0

3 years ago