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Sliva [168]
3 years ago
7

Will give brainliest if right O D. The points seem to be clustered around a line.

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

D. The points seem to be clustered around a line.

Step-by-step explanation:

The scatterplot points are spread out and forming a line, not around a point.

There are two outliers.

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Solve: e^2x + 5 = 4<br> help pls
kaheart [24]

Answer:

The solution of the equation is x=\frac{(ln4)-5}{2} ⇒ 3rd answer

Step-by-step explanation:

* Lets explain how to solve this problem

- The function f(x) = e^x is called the (natural) exponential function

- The natural logarithm (㏑), or logarithm to base e, is the inverse

 function to the natural exponential function

∵ e^{2x+5}=4 is an exponential function

∴ We can solve it by using the inverse of e (㏑)

- Remember:

# ln(e)=1

# ln(e^{m})=m(ln(e))=m

- Insert ln in both sides

∴ ln(e^{2x+5})=ln(4)

∵ ln(e^{2x+5})=(2x+5)ln(e)=2x+5

∴ 2x + 5 = ㏑(4)

- Subtract 5 from both sides

∴ 2x = ㏑(4) - 5

- Divide both sides by 2 to find x

∴ x=\frac{ln(4)-5}{2}

* The solution of the equation is x=\frac{(ln4)-5}{2}

4 0
4 years ago
Read 2 more answers
Consider the given density curve. A curve starts at (0, 0), curves up to maximum point (3, question mark), and then decreases do
stepladder [879]

Answer:

5

Step-by-step explanation:

because i did it its 5

4 0
3 years ago
Elliot ate 3/8 of a pizza that was cut into 8 slices. How much is left?
Yuliya22 [10]

Answer:

5/8

Step-by-step explanation:

8 0
3 years ago
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What is the end behavior of the polynomial function
PSYCHO15rus [73]
Even-degree polynomials behave like quadratics, while odd-degree polynomials behave like cubic graphs. If an even-degree polynomial has a positive leading coefficient, the two ends of the graph point upward. If an even-degree polynomial has a negative leading coefficient, the two ends of the graph point downward. If an odd-degree polynomial is positive, the left end points down and the right end points up. If an odd-degree polynomial has a positive leading coefficient, the left end points up and the right end points down.
3 0
3 years ago
Triangles A and B have vertical heights x cm and (x+3) cm respectively. The areas of Triangles A and B are 30cm² and 32cm² respe
PolarNik [594]

Answer:

Hi,

Step-by-step explanation:

Let say a the base of the triangle A and b the base of the triangle B.

a)\\\left\{\begin{array}{ccc}\dfrac{a*x}{2}&=&30\\\dfrac{b*(x+3)}{2}&=&32\\b=a-4\\\end{arraqy}\right.\\\\(i): a=\dfrac{60}{x}\\\\(ii): b=\dfrac{64}{x+3}\\\\b)\\\dfrac{64}{x+3}=\dfrac{60}{x}-4\\\\64x=(60-4x)*(x+3)\\\\4x^2+16x-180=0\\\\x^2+4x-45=0\\\\\Delta=16+4*45=196=14^2\\x=\dfrac{-4+14}{2}=5\ or\ x=\dfrac{-4-14}{2}=-9\ (impossible)\\So\ x=5,\ a=\dfrac{60}{5}=12, b=\dfrac{64}{5+3}=8\\\\Area\ of\ A=12*5/2=30\\Area\ of\ B=8*8/2=32\\\\Height\ of\ triangle\ B=x+3=5+3=8.\\

3 0
2 years ago
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