Here's how you solve this. So, x+y=2, right? Let's isolate x. x+y-y=2-y. x=2-y. NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y! 3x+2y=5. 3(2-y)+2y=5. (3*2)+(3*-y)+2y=5. 6+(-3y)+2y=5. 6+(-y)=5. 6+(-y)-6=5-6. -y=-1. -y/-1=-1/-1. y=1.
So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2. x+1=2. x+1-1=2-1. x=1. 1+1=2, so that works; let's check the other equation. 3(1)+2(1)=5. 3+2=5. 5=5. That's correct!
Answer: x=1, y=1
Answer:
The intensity of the first earthquake is 6.31 times the second one
Step-by-step explanation:
The given formulae is M=log(
)
Here for both the earthquakes the value of S is same.
Let the Intensity of the first earthquake be I1 and the second be I2.
Given M1=7.5
M2=6.7
Now M1=log(
)------1
M2=log(
)-----2
Now subtract 1 and 2 we get
M1-M2=log(
)
I1/I2=
I1=I2(
I1=I2*6.31
Answer:
51
Step-by-step explanation:
11+(-7)^2-9 - original
11+49-9 - square the -7, since its in brackets the negative applies too and a negative x a negative = positive, so it ends up as 7x7+49
60-9 - add both positives 11+49=60
51 - subtract 9 from 60, 60-9=51
Answer:
16
Step-by-step explanation:
Hope you get it.
You would just convert 5 1/3 into a improper fraction 16/3=16/3