<h3>
Answer:</h3>
- 6 large prints
- 12 small prints
<h3>
Step-by-step explanation:</h3>
<em>Numerical Reasoning</em>
Consider a set of prints that consists of 2 small prints and one large print (that is, twice as many small prints as large). The value of that set will be ...
... 2×$20 +45 = $85
To have revenue of at least $510, the studio must sell ...
... $510/$85 = 6
sets of prints. That is, the studio needs to sell at least 6 large prints and 12 small ones.
_____
<em>With an equation</em>
Let x represent the number of large prints the studio needs to sell. Then 2x will represent the number of small prints. Total sales will be ...
... 20·2x +45·x ≥ 510
... 85x ≥ 510
... x ≥ 510/85
... x ≥ 6
The studio needs to sell at least 6 large prints and 12 small prints.
Answer:
x = 0
, y = 4
Step-by-step explanation:
Solve the following system:
{y = 4 - 3 x | (equation 1)
x + 2 y = 8 | (equation 2)
Express the system in standard form:
{3 x + y = 4 | (equation 1)
x + 2 y = 8 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 x + y = 4 | (equation 1)
0 x+(5 y)/3 = 20/3 | (equation 2)
Multiply equation 2 by 3/5:
{3 x + y = 4 | (equation 1)
0 x+y = 4 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 0 | (equation 1)
0 x+y = 4 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 0 | (equation 1)
0 x+y = 4 | (equation 2)
Collect results:
Answer: {x = 0
, y = 4
Answer:
the answer is 1
because 1 is not multiple in our self
