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Marina86 [1]
3 years ago
8

The surface area of the square pyramid is 16 square inches. Find the value of x.

Mathematics
2 answers:
Andrew [12]3 years ago
8 0

Answer:

height h = 2.8284271247462 in

Step-by-step explanation:

height h = 2.8284271247462 in

slant height s = 3 in

side length a = 2 in

lateral edge length e = 3.1622776601684 in

1/2 side length r = 1 in

volume V = 3.7712361663283 in³

lateral surface area L = 12 in²

base surface area B = 4 in²

total surface area A = 16 in²

cluponka [151]3 years ago
3 0

Answer:

x=6 2/5

Step-by-step explanation:

I don't know how to explain other than doing the math of (x*5)/2=16

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Solve: 2x2-x = 21 {-7/2,3} {-3, 7/2}​
Sergio039 [100]

Answer:

The answer is (-3,7/2)

Step-by-step explanation:

2 {x}^{2}  - x - 21 = 0 \\ (2x - 7)(x + 3) = 0 \\ 2x - 7 = 0 \:  \:  \: or \:  \: x + 3 = 0 \\ x =  \frac{7}{2}  \:  \: and \: x =  - 3

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4 0
3 years ago
The quality control manager of a soda manufacturing company wishes to use a significant level of 0.05 to test whether the variab
Alex17521 [72]

Answer: 1.645

Step-by-step explanation:

Given : The quality control manager of a soda manufacturing company wishes to use a significant level of 0.05 to test whether the variabilities in the amount of soda in the company's 16 OZ bottles is more than the variabilities in the company's 12 OZ bottles.

Let \sigma_1^2 represents the variance for 16 OZ bottles and \sigma_2^2 represents the variance for 12 OZ bottles.

The Null and Alternative Hypothesis will be  :-

H_0:\sigma_1^2\geq\sigma_2^2

H_1:\sigma_1^2, since alternative hypothesis is left-tailed , then the test is left-tailed test.

By using the standard normal distribution table for z, the critical value for this hypothesis:-

z_{\alpha}=z_{0.05}=1.645

6 0
4 years ago
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Answer:

discount=MP-SP

=Rs420-Rs405

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Step-by-step explanation:

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3 years ago
What is 42= -7 × (z - 3)?
Agata [3.3K]

Answer:

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Step-by-step explanation:

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Find the inverse of the function. Show work. <br> g(x)= - 3/x-2 +2
4vir4ik [10]

Answer:

\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}

Step-by-step explanation:

We are given the function:

\displaystyle g(x)=-\frac{3}{x-2}+2

Let's find the inverse of g.

Call y=g(x):

\displaystyle y=-\frac{3}{x-2}+2

We need to solve for x. Multiply both sides by x-2 to eliminate denominators:

y(x-2)=-3+2(x-2)

Operate:

yx-2y=-3+2x-4

Collect the x's to the left side and the rest to the right side of the equation:

yx-2x=-3-4+2y

Factor the left side and operate on the right side:

x(y-2)=-7+2y

Solve for x:

\displaystyle x=\frac{-7+2y}{y-2}

Interchange variables:

\displaystyle y=\frac{-7+2x}{x-2}

Call y as the inverse function:

\boxed{\displaystyle g^{-1}(x)=\frac{-7+2x}{x-2}}

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3 years ago
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