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bogdanovich [222]
3 years ago
8

PLZZZZ HELP ASAP PLZZZ

Mathematics
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer:

1. (5x - 2) + (2x - 2) + x = 180^{o}

2. m<J = 113^{o}

3. m<K = 44^{o}

4. m<L = 23^{o}

Step-by-step explanation:

Generally, the sum of angles in a triangle = 180^{o}.

So that;

m<J + m<K + m<L = 180^{o}

(5x - 2) + (2x - 2) + x = 180^{o}

5x + 2x + x -2 -2 = 180^{o}

8x - 4 = 180^{o}

8x = 180^{o} + 4

8x = 184

x = \frac{184}{8}

x = 23^{o}

Thus,

m<J = (5x - 2)

       = 5(23) - 2

       = 113^{o}

m<K = (2x -2)

        = 2(23) - 2

        = 44^{o}

m<L = x

       = 23^{o}

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 and you can compute d by:
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yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

sin^4(x) + cos^4(x)

We can rewrite this as:

(sin^2(x))^2 + (cos^2(x))^2

Now we can add and subtract cos^2(x)*sin^2(x) to get:

(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)

We can complete squares to get:

(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2

and we know that:

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then:

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This is the closest expression to what you wrote.

We also know that:

sin(x)*cos(x) = (1/2)*sin(2*x)

If we replace that, we get:

1 - \frac{sin^2(2*x)}{2}

Then the simplification is:

cos^4(x) + sin^4(x)  = 1 - \frac{sin^2(2*x)}{2}

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