1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katarina [22]
3 years ago
5

A polynomial is factored using algebra tiles

Mathematics
2 answers:
dezoksy [38]3 years ago
8 0

Answer:

A) x^2-2x-8

Step-by-step explanation:

The polynomial factored is equal to the area of the algebra tiles. This means the quadratic is

x^2 + x+ x -x -x -x -x-1-1-1-1-1-1-1-1\\x^2-2x-8

After writing out each tile as a term, combine like terms to simplify. This ia the quadratic.

x^2-2x-8

Ludmilka [50]3 years ago
3 0

Answer: x2-2x-8

Step-by-step explanation:

On edgunity it is

You might be interested in
Select the correct answer. Which sentence correctly describes a data set that follows a normal distribution with a standard devi
Artyom0805 [142]

Answer: Option (c) is correct.

68% of the data points lie between 10 and 18.

Step-by-step explanation: Given :  a normal distribution with a standard deviation of 4 and a mean of 14

We have to choose the  sentence that correctly describes a data set that follows a normal distribution with a standard deviation of 4 and a mean of 14.

Since, given 68% data.

We know mean of data lies in middle.

And standard deviation is distribute equally about the mean that is 50% of values less than the mean  and 50% greater than the mean.

So, 68% of data lies

mean - standard deviation = 14 - 4 = 10

mean + standard deviation = 14 + 4 = 18

So, 68% of the data points lie between 10 and 18.

5 0
2 years ago
Read 2 more answers
Madison has a collection of 220 coins. How many coins represent 5% of her
ella [17]

Answer:

11

220/x=100/5

(220/x)*x=(100/5)*x       - we multiply both sides of the equation by x

220=20*x       - we divide both sides of the equation by (20) to get x

220/20=x

11=x

x=11.

4 0
3 years ago
Read 2 more answers
The linear inequality y<-2/3x+2 is graphed. Determine a solution for the inequality. A) (0,2) B) (3,0) C) (0,0) D) (0,3)
jenyasd209 [6]

Hello!

The graph y < -2/3x + 2 has a dotted line. That means that any points on the dotted line or not shaded, is not a solution to this inequality. Since we are given 4 choices, we can substitute those values into the given inequality to see if it is true.

A) (0, 2)

2 < -2/3(0) + 2

2 < 2, this is false.

B) (3, 0)

0 < -2/3(3) + 2

0 < -2 + 2

0 < 0, this is false.

C) (0, 0)

0 < -2/3(0) + 2

0 < 2, this is true.

D). (0, 3)

3 < -2/3(0) + 2

3 < 2, this is false.

To check if choice C) (0, 0) is true, we should look at the given graph.

Since (0, 0) is in the shaded area, and is not graphed on the dotted line, therefore, a solution to this linear inequality is C, (0, 0).

5 0
4 years ago
Please help me and fast please!!!!
Novosadov [1.4K]

Answer:

b I think

Step-by-step explanation:

it would need to be a positive line so that eliminated A. also D is not it because the calories will go up, and not stay the same. this leaves is with B and C. I think that it is B because you have to start at 0. hope this helped!

4 0
3 years ago
Read 2 more answers
please help solve this question !! *the question is in the pic* (answer thoroughly and make sure to explain step my step and if
Lady bird [3.3K]

Step-by-step explanation:

<em>ap</em><em>p</em><em>ly </em><em>angle</em><em> </em><em>sum </em><em>property</em><em> </em><em>of </em><em>triangle</em><em> </em><em>in </em><em>the </em><em>given</em><em> </em><em>traingle </em><em>(</em><em> </em><em>instead</em><em> </em><em>of </em><em>this </em><em>u </em><em>can </em><em>write</em><em> </em><em>sum </em><em>of </em><em>all </em><em>the </em><em>interior</em><em> </em><em>angles </em><em>of </em><em>triangle</em><em> </em><em>is </em><em>1</em><em>8</em><em>0</em><em>°</em><em>)</em>

<em>so,</em>

<em>→</em><em> </em><em>8</em><em>0</em><em>°</em><em> </em><em>+</em><em> </em><em>5</em><em>0</em><em>°</em><em> </em><em>+</em><em> </em><em>x </em><em>=</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em>

<em>→</em><em> </em><em>1</em><em>3</em><em>0</em><em>°</em><em> </em><em>+</em><em> </em><em>x </em><em>=</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em>

<em>→</em><em> </em><em>x </em><em>=</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>1</em><em>3</em><em>0</em><em>°</em>

<em>→</em><em> </em><em>x </em><em>=</em><em> </em><em>5</em><em>0</em><em>°</em>

<em>therefore</em><em>,</em><em> </em><em>value</em><em> </em><em>of </em><em>x </em><em>is </em><em>5</em><em>0</em><em>°</em><em>.</em>

<em><u>hope </u></em><em><u>this</u></em><em><u> answer</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care</u></em><em><u> </u></em><em><u>and </u></em><em><u>may </u></em><em><u>u</u></em><em><u> have</u></em><em><u> a</u></em><em><u> great</u></em><em><u> day</u></em><em><u> ahead</u></em><em><u>!</u></em><em><u>.</u></em>

7 0
2 years ago
Read 2 more answers
Other questions:
  • Help me please give brainiest
    8·1 answer
  • How do i solve 0.97 on a decimal number line?
    7·1 answer
  • Mags and Vector are playing a board game. They use a spinner to determine if they should move forward or backward. They roll a n
    7·1 answer
  • 31 workers are working on a construction site. 5 more workers work for company A than for company B. How many workers work for e
    12·1 answer
  • 3. Approximate square root v15
    8·1 answer
  • 6 5/6 - 3 1/3 Simplified
    11·1 answer
  • Which negative angle is equivalent to 275°?<br> O A. -75°<br> OB. -65°<br> O C. -95°<br> OD. -85
    9·1 answer
  • -7.
    5·1 answer
  • ASAP PLS ANSWER HELP
    5·2 answers
  • The sides of a square have length s.<br> 4 Write a formula for the perimeter P of the square.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!