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3 years ago

A polynomial is factored using algebra tiles

Mathematics

2 answers:

dezoksy [38]3 years ago

8 0

Answer:

A) $x^2-2x-8$

Step-by-step explanation:

The polynomial factored is equal to the area of the algebra tiles. This means the quadratic is

$x^2 + x+ x -x -x -x -x-1-1-1-1-1-1-1-1\\x^2-2x-8$

After writing out each tile as a term, combine like terms to simplify. This ia the quadratic.

$x^2-2x-8$

Ludmilka [50]3 years ago

3 0

Answer: x2-2x-8

Step-by-step explanation:

On edgunity it is

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B) State a valid formula for multiplying out (A + B)(A − B)

Diano4ka-milaya [45]

(A+B)(A-B) = A^2-B^2.

It's equality constant

8 0

3 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

Jobisdone [24]

Answer:

$f(x)=x^4-9x^2-50x-150$

Step-by-step explanation:

Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).

By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.

Therefore the polynomial in factored form is $f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))$

We expand to get: $f(x)=(x^2-2x-15)(x^2+2x+10)$

We expand further to get:\

$f(x)=x^4-9x^2-50x-150$

3 0

3 years ago

30 years ago zoe was 2/3 as old as luke, 18 years ago zoe was 5/6 as old as luke how old are they now

barxatty [35]

Based on the mathematical statements, Zoe is 56 years old and Luke is 66 years old, now

<h3>How to determine how old they are now?</h3>

From the question, we have the following statements that can be used in our computation:

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

Let their present ages be represented as

Zoe = x

Luke = y

So, we have the following representations

<u>30 years ago</u>

Zoe was 2/3 as old as Luke

x - 36 = 2/3(y - 36)

<u>18 years ago</u>

Zoe was 5/6 as old as Luke

x - 18 = 5/6(y - 18)

So, we have the following system of equations

x - 36 = 2/3(y - 36)

x - 18 = 5/6(y - 18)

Make x the subject in x - 18 = 5/6(y - 18)

x = 5/6(y - 18) + 16

Substitute x = 5/6(y - 18) + 16 in x - 36 = 2/3(y - 36)

5/6(y - 18) + 16 - 36 = 2/3(y - 36)

Open the brackets

5/6y - 15 + 16 - 36 = 2/3y - 24

Evaluate the like terms

5/6y - 35 = 2/3y - 24

Multiply through by 6

5y - 210 = 4y - 144

Evaluate the like terms

y = 66

Substitute y = 66 in x = 5/6(y - 18) + 16

x = 5/6(66 - 18) + 16

Evaluate

x = 56

Recall that

Zoe = x

Luke = y

So, we have

Zoe = x = 56

Luke = y = 66

Hence, they are 56 and 66 years, now