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quester [9]
3 years ago
9

The first thing you must consider in any type of communication is ______.

Computers and Technology
2 answers:
vivado [14]3 years ago
6 0

The correct answer to this questio is option letter C

Wittaler [7]3 years ago
5 0
As for this problem together with the options as answers presented with it, the most probable and the most likely answer would be C. the purpose of the communication.

The first thing you must consider in any type of communication is the purpose of the communication itself. Determining the purpose behind the communication would, in turn, pave way to determining the other things that is needed to be determined such as the type of communication, the style of communication, the timing of the communication, and so on and so forth.
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Given the lists list1 and list2, not necessarily of the same length, create a new list consisting of alternating elements of lis
tester [92]

Answer:

The following code is written in Python Programming Language.

Program:

list1=[1,2,3]

 # initialized the list type variable

list2=[4,5,6,7,8]

  # initialized the list type variable

list3=[]

   # initialized the empty list type variable

for j in range(max(len(list1), len(list2))):   #set for loop

 if j<len(list1):

  #set if statement

   list3.append(list1[j])

  #value of list1 appends in list3  

 if j<len(list2):

   #set if statement

   list3.append(list2[j])

  #value of list2 append in list3

print(list3)    #print the list of list3

Output:

[1, 4, 2, 5, 3, 6, 7, 8]

Explanation:

Here, we define three list type variables "list1", "list2", "list3" and we assign value in only first two variables "list1" to [1, 2, 3] and "list2" to [4, 5, 6, 7, 8] and third list is empty.

Then, we set the for loop and pass the condition inside it we pass two if conditions, in first one we compare the list1 from variable "j" inside it the value in list1 will append in list3, and in second one we compare "j" with list two and follow the same process.

After all, we print the list of the variable "list3".

5 0
3 years ago
g Create a package named lab7 (no spaces, ALL in lowercase) where you will place your lab files. Write a class FilterWith with a
sweet [91]

Answer:

See explaination

Explanation:

import java.util.ArrayList;

import java.util.Scanner;

public class ListFilter

{

public static void filterRange(ArrayList<Integer> list,int min, int max)

{

ArrayList<Integer> listNew=new ArrayList<Integer>();

for(int i=0;i<list.size();i++)

{

if(list.get(i)>=min && list.get(i)<=max) //Checking if element is between min and max

{

listNew.add(list.get(i));

}

}

list.removeAll(listNew); //removing all elements from list.

}

public static void main(String[] args)

{

ArrayList<Integer> list=new ArrayList<Integer>();

list.add(4);

list.add(7);

list.add(9);

list.add(2);

list.add(7);

list.add(7);

list.add(5);

list.add(3);

list.add(5);

list.add(1);

list.add(7);

list.add(8);

list.add(6);

list.add(7);

Scanner sc=new Scanner(System.in);

System.out.println("Enter min : ");

int min=sc.nextInt();

System.out.println("Enter Max : ");

int max= sc.nextInt();

filterRange(list, min, max);

//Displaying new List

for(int i=0;i<list.size();i++)

{

System.out.print(list.get(i)+" ");

}

}

}

3 0
3 years ago
Why are charts and graphs included in documents rather than just raw data?
trapecia [35]

Answer:

It's more organized and easier to look at

Explanation:

If it was just the raw data, it would take more time to analize, rather than it already being in a chart or graph

4 0
3 years ago
Write a program whose input is two integers. Output the first integer and subsequent increments of 10 as long as the value is le
Lubov Fominskaja [6]

Answer:

import java.util.Scanner;

public class TestClock {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter two integer numbers");

       int num1 = in.nextInt();

       int num2 = in.nextInt();

       int newSum=num1+10;

       System.out.println("The first number is "+num1);

       do{

          System.out.println(newSum);

          newSum +=10;

       }while (newSum <=num2);

   }

}

Explanation:

Using Java Programming language

  1. Prompt user for the two inputs and save them as num1 and num2(Using the scanner class)
  2. Create a new Variable newSum = num1+10
  3. Create a do...while loop to continually print the value of newSum, and increment it by 10 while it is less or equal to num2
3 0
3 years ago
An OR function nested in an IF function results in
tester [92]
I think is the second one
5 0
3 years ago
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