Answer:
Following are the program in python language
def prob3_6(k): #function definition
c = 0 #variable declaration
while k != 1: #iterating the while loop
print(k) #print k
if k % 2 == 0:#check if condition
k= k // 2 #divisible by 2
else: #else condition
k = k * 3 + 1
c = c + 1
print(k) #print k
print c #print count
prob3_6(3)#function call
Output:
3
10
5
16
8
4
2
1
7
Explanation:
Following are the description of program
- Create a function "prob3_6" in this function we passing an integer parameter of type "int" named "k".
- Inside that function we declared a variable "c" of type "int" that is used for counting purpose .
- After that we iterated the while for print the value of when it is not equal to 1 .
- We check if condition when k gives 0 on modulus then k is divisible by 2 otherwise else block will be executed in the else part we multiply by 3 to k and add 1 to the k variable .
- Finally print "k" and "c"
Budget and time is the answer
Ithink that the answer is C)
Answer:
In a STAR TOPOLOGY network, each device on the network is attached to a central router. If the router fails, then the other devices will be unable to communicate, but if only one connected device fails, then all other devices will still be able to communicate.
Explanation:
In this type of topology all the computers are connected to a single router through a cable. This router is the central node and all others nodes are connected to the central node.
Two. One for encryption, and one for decryption. RSA is an example of an asymmetric encryption algorithm.
