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svetlana [45]
3 years ago
12

If the product of two identical number is one thousand twenty four. Find out of the numbers​

Mathematics
2 answers:
NeX [460]3 years ago
7 0

Answer:

32

Step-by-step explanation:

Let the unknown number be n.

When multiplied together, the product is 1,024. Therefore:

n\cdot n=1024

Combine:

n^2=1024

Take the square root of both side:

n=\sqrt{1024}=32

Therefore, the unknown number is 32.

GaryK [48]3 years ago
3 0

Answer:

32

Step-by-step explanation:

1,024 will be a perfect square if it is the product of 2 of the same numbers:

Calculate the square root of 1024:

\sqrt{1024}

= 32

So, the number is 32

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Which pair(s) of expression are equal in value? Check all that apply
ankoles [38]

Note: Since the symbols for greatest integer function (GIF) and least integer function (LIF) are not given, I will be using the words GIF and LIF in the solution

GIF x means largest integer less than or equal to x, and LIF x means least integer greater than or equal to x.

We need to determine which expressions are equal

Option 1: GIF 4.9 and LIF 3.1

GIF 4.9 =  3

LIF 3.1 = 4

Hence GIF 4.9 ≠ LIF 3.1

Option 2: GIF 15.2 and GIF 14.8

GIF 15.2 = 15

GIF 14.8 = 14

Hence, GIF 15.2 ≠ GIF 14.8

Option 3: GIF -6 and LIF -6

GIF -6 = -6

LIF -6 = -6

Hence, GIF -6 = LIF -6

Option 4: LIF -3.2 and LIF -2.6

LIF -3.2 = -2

LIF -2.6 = -1

Hence, LIF -3.2 ≠ LIF -2.6

Hence, only in Option C the pair of expressions are equal.

3 0
3 years ago
Read 2 more answers
The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament.
NeX [460]

Answer:

Step-by-step explanation:

Hello!

(Data and full text attached)

The stem and leaf plot is a way to present quantitative data.  Considering two-digit numbers, for example 50, the tens digits are arranged in the stem and the units determine the leafs.

So for the stem and leaf showing the digs of the top players of the tournament, the observed data is:

41, 41, 43, 43, 45, 50, 52, 53, 54, 62, 63, 63, 67, 75, 97

n= 15

Note that in the stem it shows the number 8, but with no leaf in that row, that means that there were no "eighties" observed.

a) 6 Players had more than 60 digs.

b)

To calculate the mean you have to use the following formula:

X[bar]= ∑x/n= (41 + 41 + 43 + 43 + 45 + 50 + 42 + 53 + 54 + 62 + 63 + 63 + 67 + 75 + 97)/15= 849/15= 56.6 digs

To calculate the median you have to calculate its position and then identify its value out of the observed data arranged from least to greatest:

PosMe= (n+1)/2= (15+1)/2= 8 ⇒ The median is in the eight place:

41, 41, 43, 43, 45, 50, 42, 53, 54, 62, 63, 63, 67, 75, 97

The median is Me= 53

53 is the value that separates the data in exact halves.

The mode is the most observed value (with more absolute frequency).

Consider the values that were recorded more than once

41, 41

43, 43

63, 63

41, 43 and 63 are the values with most absolute frequency, which means that this distribution is multimodal and has three modes:

Md₁: 41

Md₂: 43

Md₃: 63

The Range is the difference between the maximum value and the minimum value of the data set:

R= max- min= 97 - 41= 56

c)

The distribution is asymmetrical, right skewed and tri-modal.

Md₁: 41 < Md₂: 43 < Me= 53 < X[bar]= 56.6 < Md₃: 63

Outlier: 97

d)

An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.  

Considering the 1st quartile (Q₁), the 3rd quartile (Q₃) and the interquartile range IQR, any value X is considered an outlier if:

X < Q₁ - 1.5 IQR

X > Q₃ + 1.5 IQR

PosQ₁= 16/4= 4

Q₁= 43

PosQ₃= 16*3/4= 12

Q₃= 63

IQR= 63 - 43= 20

Q₁ - 1.5 IQR = 43 - 1.5*20= 13 ⇒ There are no values 13 and below, there are no lower outliers.

Q₃ + 1.5 IQR = 63 + 1.5*20= 93 ⇒ There is one value registered above the calculated limit, the last observation 97 is the only outlier of the sample.

The mean is highly affected by outliers, its value is always modified by the magnitude of the outliers and "moves" its position towards the direction of them.

Calculated mean with the outlier: X[bar]= 849/15= 56.6 digs

Calculated mean without the outlier: X[bar]= 752/14= 53.71 digs

I hope this helps.

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3 years ago
10 to the zero power times 0.23=
Lana71 [14]
The answer is 0.23. Ned an explanation
5 0
3 years ago
Convert 123 cm to dam
kondaur [170]
123 centimeters into dekameters
0.123
10 centimeters = 1 decimeter
100 decimeters = 1 dekameter
Therefore, 100 centimeters = 10 decimeters = 0.1
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8 0
3 years ago
Hey i am not smart but what is <br> <img src="https://tex.z-dn.net/?f=83%5Cfrac%7B1%7D%7B3%7D%20minus%20%5Cfrac%7B2%7D%7B3%7D" i
Ray Of Light [21]
It would be 82 2/3 since 1/3 minis 2/3 would equal -1/3 you subtract that from 83 and get 82 2/3
6 0
3 years ago
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