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3 years ago

Hello, I gotta turn it turn in this question today, help!!!!!!

Mathematics

1 answer:

Sladkaya [172]3 years ago

3 0

Answer:

2 or -2

Step-by-step explanation:

If x² - 8x = -12

Step 1

We find x by solving

x² - 8x = -12

We equate to zero

x² - 8x + 12 = 0

We factorise

x² - 6x - 2x + 12 = 0

x(x - 6) -2(x - 6) = 0

(x - 6) (x - 2) = 0

x - 6 = 0, x = 6

x - 2 = 0, x = 2

x = 6 or 2

Step 2

What is x - 4?

When x = 6

= 6 - 4 = 2

When x = 2

= 2 - 4 = -2

Therefore, x - 4 = 2 or -2

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Plz help it's due tomorrow

posledela

Most of the answers are in the book. 1&2 is based on vocabulary and 8&9 are on the chart

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3 years ago

Area of a park is exactly halfway between 2.4 and 2.5 acres, what is the area of the park

vitfil [10]

2.40, 2.41, 2.42, 2.43, 2.44, 2.45, 2.46, 2.47 ,2.48 ,2.49, 2.50

2.45 is area

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3 years ago

Which pairs of rectangles are similar polygons?<br> Select each correct answer.

iragen [17]

Answer:

The bottom two

Step-by-step explanation:

[] Similar beings their sides have equivalent ratios to each other

[] See attached

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

8 0

3 years ago

A tank contains 10 liters of pure water. Saline solution with a variable concentration 5 grams of salt per liter is pumped into

algol [13]

Answer:

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

Step-by-step explanation:

The mass flow rate dQ(t)/dt = mass flowing in - mass flowing out

Since 5 g/L of salt is pumped in at a rate of 4 L/min, the mass flow in is thus 5 g/L × 4 L/min = 20 g/min.

Let Q(t) be the mass present at any time, t. The concentration at any time ,t is thus Q(t)/volume = Q(t)/10. Since water drains at a rate of 4 L/min, the mass flow out is thus, Q(t)/10 g/L × 4 L/min = 2Q(t)/5 g/min.

So, dQ(t)/dt = mass flowing in - mass flowing out

dQ(t)/dt = 20 g/min - 2Q(t)/5 g/min

Since the salt just begins to be pumped in, the initial mass of salt in the tank is zero. So Q(0) = 0

So, the initial value problem is thus

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

3 0

2 years ago

Natalia and Riley hike 10 6/11 miles. In one day, Ricardo hiked to 2 3/4 times as far as Natalia and Riley hiked. how far did he

Maksim231197 [3]

Answer:

Ricardo hiked 29 miles.

Step-by-step explanation:

10 6/11 x 2 3/4

convert

116/11 x 11/4 = 1276/44

1276/44 = 29

7 0

3 years ago