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Aleksandr-060686 [28]
4 years ago
7

What is the equation of the line?

Mathematics
1 answer:
sertanlavr [38]4 years ago
7 0
I need a picture please
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What is the standard form equation of the line shown below?
Pavlova-9 [17]

Answer:

C.

Step-by-step explanation:

14/3 = 4.7 which seems about right for the Y-intercept & the gradient is - 1/3.

Gradient = rise /run

= 1/3

Hope this helps!

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What fraction of 1 quart is 3 cups
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There are 4 cups in a quart so 3 cups is 3/4 a quart
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Find the y-intercept of the following function:<br><br> <img src="https://tex.z-dn.net/?f=2x%20-%204y%20%3D%209" id="TexFormula1
fomenos

Hi there!

\large\boxed{0, -\frac{9}{4}  }

2x - 4y = 9

Begin by isolating the y variable by moving 2x to the right-hand side of the equation. (Subtract 2x from both sides):

2x - 2x - 4y = 9 - 2x

-4y = 9 - 2x

Further isolate by dividing both sides by -4:

-4y / (-4) = (9 - 2x) / (-4)

y = -9/4 - 2x/(-4)

Simplify further:

y = -9/4 + 1/2x

y = 1/2x - 9/4

The "b" value is the y-intercept, therefore:

x = 0 at y = -9/4

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Use the remainder theorem to find which of the following is NOT a factor of x^3 – 4x^2 – 4x + 16.
nataly862011 [7]

Answer: x - 12 is not a factor.

Step-by-step explanation:

The equation

x³ - 4x² - 4x + 16

To know which of the following is a factor , we continue to find the value of x and substitute into the equation and see the one that gives zero. The one that gives zero is the factor.

(a) x + 2

If x + 2 = 0

x = -2, now substitute for x in the equation and find out if it will be zero.

x³ - 4x² - 4x + 16 = (-2)³ - 4(-2)² - 4(-2) + 16.

= -8 - 16 + 8 + 16

= 0.

Therefore, x + 2 is a factor.

(b) x - 12

If x - 12 = 0, then x = 12

x³ - 4x² - 4x + 16

(12)³ - 4(12)² - 4(12) + 16

1728 - 576 - 48 + 16

= 1,120 , not a factor.

(c) x - 2

If x - 2 = 0, then x = 2

x³ - 4x² - 4x + 16

(2)³ - 4(2)² - 4(2) + 16

8 - 16 - 8 + 16

= 0, Therefore, x - 2 is a factor.

(d) x - 4

If x - 4 = 0, x = 4

x³ - 4x² - 4x + 16

(4)³ - 4(4)² - 4(4) + 16

48 - 48 - 16 + 16

= 0,therefore, x - 4 is also a factor.

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