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3 years ago

Write the phrase as an expression. the product of 3+12 an expression is _____

Mathematics

1 answer:

Dima020 [189]3 years ago

8 0

Answer:

Writing expressions | Math (article) | Khan Academy

Step-by-step explanation:

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A quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line. The pencils ha

amm1812

Answer:

The P-value you would use to test the claim that the population mean of pencils produced in that factory have a mean length equal to 18.0 cm is 0.00736.

Step-by-step explanation:

We are given that a quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line.

The pencils have a mean length of 17.9 cm. Given that the population standard deviation is 0.25 cm.

Let $\mu$ = population mean length of pencils produced in that factory.

So, Null Hypothesis, $H_0$ : $\mu$ = 18.0 cm {means that the population mean of pencils produced in that factory have a mean length equal to 18.0 cm}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 18.0 cm {means that the population mean of pencils produced in that factory have a mean length different from 18.0 cm}

The test statistics that will be used here is One-sample z-test statistics because we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean length of pencils = 17.9 cm

$\sigma$ = population standard deviation = 0.25 cm

n = sample of pencils = 45

So, the test statistics = $\frac{17.9-18.0}{\frac{0.25}{\sqrt{45} } }$

= -2.68

The value of z-test statistics is -2.68.

Now, the P-value of the test statistics is given by;

P-value = P(Z < -2.68) = 1 - P(Z $\leq$ 2.68)

= 1- 0.99632 = 0.00368

For the two-tailed test, the P-value is calculated as = 2 $\times$ 0.00368 = 0.00736.

7 0

3 years ago

Suppose the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1

denis23 [38]

Given that the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1 ounces.

The probability of a normally distributed data between two values (a, b) is given by:

$P(a\ \textless \ X\ \textless \ b)=P\left(z\ \textless \ \frac{b-\mu}{\sigma/\sqrt{n}} \right)-P\left(z\ \textless \ \frac{a-\mu}{\sigma/\sqrt{n}} \right) \\ \\ =P(7.5\ \textless \ X\ \textless \ 8.5)=P\left(z\ \textless \ \frac{8.5-8.0}{1.1/\sqrt{6}} \right)-P\left(z\ \textless \ \frac{7.5-8.0}{1.1/\sqrt{6}} \right) \\ \\ =P(z\ \textless \ 1.113)-P(-1.113)=0.8672-0.1328=0.7344$

6 0

3 years ago

True or false please answer ASAP ( Brainliest )

prisoha [69]

True.

Hope this helps!

8 0

2 years ago

Read 2 more answers

find the equation of a line that passes through (2 -1) and ia parallel to y=2x+y-4=0 leave your answer in the form of y=mx+c

Oksanka [162]

Answer:

Y=2x-5

Step-by-step explanation:

Parallel m=2

Y=mx+c

-1=2(2)+c

C=-5

7 0

3 years ago

5- 55+41 = 15 3r + 55 - 61 = 7 -r + 5s - 5 = 20

Verizon [17]

Step-by-step explanation:

5-55+41=15

50+41=15

91=15

94-15

=79

3r+55-61=7

3r=7+61-55

3r=7+6

3r=13

3r/3=13/3

r=13/3

r+5s-5=20

r+5s=20+5

r+5s=25

6 0

2 years ago