Question

Please help me with this question

Answer 1

Answer:

a. 30 meters per second

b. -10 meters per second

Step-by-step explanation:

a. Average rate of change for the height from 0 to 6.6 secs can be calculated using the formula, $m = \frac{H(b) - H(a)}{b - a}$

Thus,

Where,

$a = 0, H(0) = 0$

$b = 6.6, H(6.6) = 198$

Plug in the values into the formula:

$m = \frac{198 - 0}{6.6 - 0}$

$m = \frac{198}{6.6}$

$m = 30$

b. Average rate of change for the height from 8.8 to 13.2 secs = tex] m = \frac{H(b) - H(a)}{b - a} [/tex]

Where,

$a = 8.8, H(8.8) = 44$

$b = 13.2, H(13.2) = 0$

Plug in the values:

$m = \frac{0 - 44}{13.2 - 8.8}$

$m = \frac{-44}{4.4}$

$m = -10$