Answer:
79
Step-by-step explanation: 2 4 6 8 are even numbers 1 3 5 7 9 are odds and 79 it the only one that is a odd number
#1. 4x^2 + 17 - 15 = 0
Use the roots given, and plug them in to a factored form. Then, foil! It can also be helpful to multiply the equation to get rid of decimals/fractions.
(x - 3/4)(x + 5) = 0
x^2 - 3/4x + 5x - 3 3/4 = 0
x^2 + 4.25 - 3.75 = 0 (multiply everything by 4)
4x^2 + 17 - 15 = 0
#2. y = 0, -4
Both 4y^2 and 16y contain a 4 in the coefficient and a y in the variables. Therefore, we can factor out a 4y from each.
4y(y + 4) = 0
Then, set both parts of the factored equation equal to 0.
4y = 0
y = 0
y + 4 = 0
y = -4
#3. a = 0, -3
Both 6a^5 and 18a^4 contain a 6 in the coefficient and an a in the variables. Therefore, we can factor out a 6a^4 from each.
6a^4(a + 3) = 0
Then, set both parts of the factored equation equal to 0.
6a^4 = 0
a = 0
a + 3 = 0
a = -3
#4. x = -8
We are looking for two terms that multiply to equal a * c, and add up to equal b. We know that 8 + 8 = 16, and 8 * 8 = 64. There are no negatives in this equation, therefore both signs in our factored form are positive.
(x + 8)(x + 8) = 0
x + 8 = 0
x = -8
#5. x = -8, 8
First, subtract 64 from both sides. The key word here is 'factoring.' If this was not present, there is a different way (which may be easier for some).
x^2 = 64
x^2 - 64 = 0
Next, use the difference of two squares property to factor (x - c)(x + c), and set the two binomials equal to 0.
(x - 8)(x + 8) = 0
x - 8 = 0
x = 8
x + 8 = 0
x = -8
Hope this helps!! :)
Answer:
Step-by-step explanation:
Given: Equation is 
To find: flaw in Gwendolyn's work and the correct solution to the equation.
Solution:
In the given question,
the first step is
The second step is 
(This step is obtained on multiplying 
by 
)
The third step is 
This step is wrong as on transposing 12 from left side of the equation in the second step to the right side, the following equation is obtained:
So, the correct solution is
.25 because .5 is the same as .50 and 25 divided by 2 is 25 and its .25 as a final
