Solve correct to 2 Demi meal places 8(6)^x=111 x=

Matthew and Ava have some money in the ratio 5:2. If Matthew gives $78 to Ava they will have the same amount of money. How much

MaRussiya [10]

Answer:

is d

Step-by-step explanation:

5 0

4 years ago

10. A In the adjoining Figure, ab is perpendicular to bc and ed is to cd while bc=cd . prove i) triangle abc is corresponding to

xxTIMURxx [149]

Part (i)

1) AB is perpendicular to BC, ED is perpendicular to CD, BC = CD (given)

2) Angles ABC and CDE are right angles (perpendicular lines form right angles)

3) Angles ABC and CDE are equal (all right angles are equal)

4) Angles ACB and DCE are equal (vertical angles are equal)

5) Triangles ABC and EDC are congruent (ASA)

Part (ii)

6) AB = DE (corresponding parts of congruent triangles are equal)

4 0

2 years ago

Write a word phrase that represents the expression 3q/2

Sati [7]

Three times q divided by two

Hope this helps

5 0

3 years ago

Use the given pair of functions to find and simplify expressions for the following functions and state the domain of each using

Tamiku [17]

Answer:

Given functions,

$f(x) = 3 - x^2$

$g(x) = \sqrt{x}+1$

Since, by the compositions of functions,

1. (g◦f)(x) = g(f(x))

$=g(3-x^2)$

$=\sqrt{3-x^2}+1$

Since, (g◦f) is defined,

If 3 - x² ≥ 0

⇒ 3 ≥ x²

⇒ -√3 ≤ x ≤ √3

Thus, Domain = [-√3, √3]

2. (f◦g)(x) = f(g(x))

$=f(\sqrt{x}+1)$

$=3-(\sqrt{x}+1)^2$

Since, (g◦f) is defined,

If x ≥ 0

Thus, Domain = [0, ∞)

3. (f◦f)(x) = f(f(x))

$=f(3-x^2)$

$=3-(3-x^2)^2$

$=3-9-x^4+6x^2$

$=-6+6x^2-x^4$

Since, (f◦f) is a polynomial,

We know that,

A polynomial is defined for all real value of x,

Thus, Domain = (-∞, ∞)

8 0

3 years ago

In a school machine shop, 60% of all machine breakdowns occur on lathes and 15% occur on drill presses. Let E denote the event t

RSB [31]

Answer:

A. P(EC) = 0.4

B. P(E∪E) = 0.75

C. P(EC ∩ FC) = 0.25

Step-by-step explanation:

Let us calculate -:

we are given with - P(E) = 60 and P(F) =.15,

Thus , (a) $P(E^C)=1-P(E)$

$=1-0.6$

$=0.4$

(b) P(E∪F) = P(E) + P(F)

= 0.60 + 0.15

= 0.75

(c) $P(E^C$ ∩ $F^C)$ $=1-P(E$ ∪ $F)$

$=1-0.75$

= $0.25$

Hence , the answers are -A. P(EC) = 0.4 , B. P(E∪E) = 0.75 , C. P(EC ∩ FC) = 0.25.

6 0

3 years ago