3 years ago

8<2/3(3y-6)

title="8 \leqslant \frac{2}{3} (3y - 6)" alt="8 \leqslant \frac{2}{3} (3y - 6)" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Effectus [21]3 years ago

5 0

8<=2/3(3y-6)

distribute

8<= 2y -4

add 4 to each side

12 <=2y

divide by 2

6<=y

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