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irina [24]
3 years ago
12

A • 1 = a

Mathematics
1 answer:
victus00 [196]3 years ago
6 0
This represents the identity property.
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What is the equation of a line that is perpendicular to the given line y = 2x - 3 and
Leviafan [203]

Answer:

y = -1/2x - 1

Step-by-step explanation:

Given equation:

y = 2x - 3

Given point: (x1,y1) = (-8,3)

This is in the form of y = mx + c,

so, m1 = 2

If the lines are perpendicular then the product of their slope will be - 1 i.e.

m1 x m2 = -1

2 x m2 = -1

m2 = -1/2

Now, using one point form formula,

y - y1 = m(x - x1)

or, y - 3 = -1/2( x - (-8))

or, y-3 = -1/2(x + 8)

or, y = -1/2x - 4 + 3

or, y = -1/2x - 1

This is the required equation.

3 0
3 years ago
The speed of water in a whirlpool varies inversely with the radius. If water speed is 2.5 feet per second at a radius of 30 feet
Nata [24]
The speed of the water in the 3 feet radius is 25 feet per second.
4 0
3 years ago
Read 2 more answers
Where can we put parenthesis in 21 + 21 divided by 7 to make it equivalent to 6?
DiKsa [7]

(21+21)÷7

Step-by-step explanation:

21+21=42 42÷7=6 I'm not good at explaining lol

4 0
3 years ago
Read 2 more answers
Find the surface area of the prism.
Fed [463]
What do you mean I need to see the prism ??
5 0
3 years ago
Need Help Please Explain I'm confused
a_sh-v [17]
OK.  Quite a bit of work for 5 points, but here goes:

Picture on the left:

When square roots need to be multiplied, just go ahead and
mash everything together. 

The product of        √one thing) times (√another thing

is just                     √(one thing times the other thing) .

So  √(3x²y³)  ·  2  ·  √(72x³y⁴)  is just

                               2 · √(3x²y³ · 72x³y⁴)

                       =      2 · √(216 x⁵ y⁷)

That looks pretty complicated.  But if you break it up into things that are
perfect squares, then you can pull those out of the square root.

                             2 · √(216 x⁵ y⁷)

                       =    2  · √(6·36  ·  x⁴·x  ·  y⁶·y)

The bold things are perfect squares, so take their square roots
and write those outside of the square root sign. 

                        =    2  · √(6·36  ·  x⁴·x  ·  y⁶·y)

                        =    2 · 6 · x² · y³ · √(6 · x · y)

                        =       12 x² y³   √6xy  .
________________________________________________

Middle picture:

How do you take the 8th root of something raised to a power ?
Just divide the power by 8 . 

                                    ⁸√(p²⁰· q²⁹ · r¹¹)

                              =    ⁸√(p¹⁶·p⁴  ·  q²⁴·q⁵  ·  r⁸·r³)

                              =   p² q³ r  ⁸√p⁴ q⁵ r³ 
____________________________________________

Picture on the right:

                           -3i (6  +  2i)

                     =    (-3i)·(6)  +  (-3i)·(2i)

                     =        -18i    +      -6i²

If ' i ' = √-1 , then i² = -1 .

                               -18i    +      -6i²

                           =  -18i    +      -6(-1)

                           =    -18i    +      6 .

Make it a little bit neater.  Factor out the ' 6 ':

                                 -18i    +      6

                           =   6·(-3i + 1) .
5 0
3 years ago
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