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erma4kov [3.2K]
3 years ago
13

Solve the system.

Mathematics
2 answers:
yanalaym [24]3 years ago
8 0

Answer:

the solutions are (1,4) and (0,3)

Step-by-step explanation:

step 1: Subtract the equations

step 2: refine

step 3:Plug the solutionsx=1,x=0 into y=3x^2-2x+3

step 4: verify

Ludmilka [50]3 years ago
5 0

Answer:

(0,3) and (1,4) are solution sets of given system

Step-by-step explanation:

Given that:

y= 3x^2−2x+3​  ------------- eqA

y = x + 3  ------------------ eqB

Putting value of y from eqB to eqA

x + 3 = 3x^2−2x+3

Taking all variables to left side:​

Signs pf transferred terms will be changed

3x^2−2x+3​  - x - 3 = 0

Adding like terms we get:

3x^2−3x = 0

Dividing both sides by 3 we get:

x^2 - x = 0

Now take x common:

x(x-1)= 0

So

x = 0      and   x = 1

Now put value in eqB

y = 0 + 3   and    y= 1 + 3

we get:

y = 3 and y = 4

So solution sets are:

(0,3) and (1,4)

i hope it will help you!

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Hope this helps!
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Hi guys can you guys help me with this question​
tresset_1 [31]

Answer:

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Step-by-step explanation:

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Part B:

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8 0
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Read 2 more answers
Nick bought 5 tickets to go to the amusement park for $65. If he wanted to buy 8 tickets, what would that cost him?
d1i1m1o1n [39]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

are you sure you wrote the problem here correctly ?

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