The slope of a line is calculated by dividing the one y portion of the line by one x portion of the line. In this problem we have two points which can indicate us one portion of the y axis and one portion of the x axis. If we have two points of one line, then we can calculate its slope:
Point one (x1, y1)
Point two (x2, y2)
then the slope can be calculated as:
m = (y2 - y1)/(x2 - x1)
So lets use our data:
Point one (2, 10)
Point two (5, 8)
then the slope can be calculated as:
m = (8 - 10)/(5 - 2<span>)
</span>m = -2/3
therefore the slope is negative and is -2/3
Marty read 4 times as many pages as Nelson and Jennifer COMBINED. Marty read 1,860 pages.
In total, after dividing Marty's total by 4, Jennifer and Nelson both read a total of 465 pages.
After subtracting Nelson's 240, Jennifer is then found to have read 225 pages.
B would be the best viable option, as it clearly shows that 240+?x4=1,860, which it does.
Hope this helped. Khan Academy is a great resource for any learner. :)
Answer:
x = 4.712145
Step-by-step explanation:
Given a=20 and b=28,
c = 4√74 = 34.409301068171
∠α = 35.538° = 35°32'16" = 0.62025 rad
∠β = 54.462° = 54°27'44" = 0.95055 rad
Area = 280
Perimeter = 82.409301068171
<h2><u>
_____________________________________</u></h2>
Let's solve your equation step-by-step.
9x−8=34.409301
Step 1: Add 8 to both sides.
9x−8+8=34.409301+8
9x=42.409301
Step 2: Divide both sides by 9.
x=4.712145
<h2>
Answer:</h2><h2>
x=4.712145</h2>
Answer:
<em>f(10)=290</em>
Step-by-step explanation:
<u>Function Evaluation</u>
Given a function f(x) as an explicit expression, finding f(x=a) implies substituting the value of x by a in every instance it occurs.
We are given the function:
It's required to find f(10). We replace the x for 10:
Operating:
Thus, f(10)=290
Answer:
x = 20√2 and y = 20√3.
or x = 28.28 and y = 34.64 to the nearest hundredths.
Step-by-step explanation:
Take the 2 'inside' triangles. They are similar.
So we have x / (60-40) = 40 / x
x/ 20 = 40 /x
x^2 = 800
x = √800
x = 20√2
y = √(800 + 20^2)
= √(1200)
= 20√3.
