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sladkih [1.3K]
3 years ago
5

Plzzzz help has to be done my 11:40 plzzzz will give brainliest

Mathematics
2 answers:
STatiana [176]3 years ago
8 0

Answer: B

Step-by-step explanation:

lord [1]3 years ago
5 0

Answer:

B - | 1.7 - (-1/2) |

Step-by-step explanation:

The expression that represents the distance between 1.7 and - 1/2 on a number line is

| 1.7 - (-1/2) |

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3643 in scientific notation
Lesechka [4]
3.643 x 10^3
move the decimal in between the first and second number
However many times you move the decimal, that is you exponent.
6 0
4 years ago
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
4 years ago
The wildflowers at a national park have been decreasing in numbers. There were 1200 wildflowers in the first year that the park
bonufazy [111]

Year      New flowers

1                 1200

2                 300

3                   75

There were 1200 wildflowers in the first year that the park started tracking them. Since then, there have been one fourth as many new flowers each year

Initially there are 1200 flowers and start decreasing by \frac{1}{4}

So first term is 1200 and common ratio is \frac{1}{4}.

Its a geometric sequence so summation becomes

i =1∑ ∞ 1200(\frac{1}{4})^{i-1}

Now we find the sum

We use sum formula

Sum = \frac{a}{1-r}

Where a is the first term , a= 1200

r is the common ratio , r= 1/4

Sum = \frac{1200}{1-(\frac{1}{4})}

Sum = \frac{1200}{\frac{3}{4}}

Sum = 1600 wildflowers

4 0
4 years ago
Find the probability that the mean annual preciptiation will be between 32 and 34 inches. variable is normally distributed
liq [111]
Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.

This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.  
                                                                     34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
                                                                           1.9
                                                                      32 in - 31.2 in
and that to the left of 32 in   is               z = ---------------------- = 0.421
                                                                             1.9

Know how to use a table of z-scores to find these two areas?  If not, let me know and I'll go over that with you.


My TI-83 calculator provided the following result:

normalcdf(32, 34, 31.2, 1.9) = 0.267  (answer to this sample problem)

5 0
3 years ago
A particle is moving along the number line so that its distance (in meters) from the origin at any time t (in seconds) is given
Black_prince [1.1K]

Answer:

The velocity is 17 m/s

Step-by-step explanation:

To find the velocity, we find the first differential of the displacement

That will be

S’(t) = 16t + 1/t

We simply proceed to replace t with 1

That will give;

16(1) + 1/1

= 16 + 1 = 17 m/s

8 0
3 years ago
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