745,093 rounded to the nearest thousands
2 answers:
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Answer:
The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>
Step-by-step explanation:
Given:
Initial speed of debris is,
The height 'h' of the debris above the ground is given as:
As per question, . Therefore,
Rewriting the above equation into a standard quadratic equation and solving for 't', we get:
Using quadratic formula to solve for 't', we get:
Therefore, the debris will reach a height of 56 ft twice.
When time during the upward journey, the debris is at height of 56 ft.
Again after reaching maximum height, the debris falls back and at , the height is 56 ft.
7) You have the opposite. You need the adjacent.
x = 7.79289... =
<h2>7.8</h2><h2 />8) You have the hypotenuse. You need the Opposite.
x = sin37 × 13
x = 7.8235... =
<h2>7.8</h2><h2 />9) You have the hypotenuse. You need the opposite.
x = sin59 × 11
x = 9.4288.... =
<h2>9.4</h2><h2 />10) You have the hypotenuse. You need the opposite.
x = sin53 × 11
x = 8.7459.... =
<h2>8.7</h2>