3 years ago

Given cosθ=1/3, find sin(90-θ)

1 answer:

7 0

Cos θ=1/3
cos θ=sen (90-θ)
therfore:
sen (90-θ)=1/3

To chek
θ=arc cos 1/3=70.53º

sin (90-θ)=sin (90º-70.53º)=sin 19.47≈0.3333≈1/3

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