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Montano1993 [528]
3 years ago
8

Given cosθ=1/3, find sin(90-θ)

Mathematics
1 answer:
natta225 [31]3 years ago
7 0
Cos θ=1/3
cos θ=sen (90-θ)
therfore:
sen (90-θ)=1/3

To chek
θ=arc cos 1/3=70.53º

sin (90-θ)=sin (90º-70.53º)=sin 19.47≈0.3333≈1/3
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