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lesya692 [45]
3 years ago
15

Alex has 6,000 grams of jelly beans. He is filling boxes that each hold 2 kilograms of jelly beans and selling the boxes for $9.

95. How much money will he make from selling the boxes?
Mathematics
1 answer:
ella [17]3 years ago
7 0

Answer:

29.85

Step-by-step explanation:

since a kilogram i 1000 grams and he is putting 2 kilos in each box he can only fill 3 boxes.

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A right triangle has one angle that measures 25º. What is the measure of the other acute<br> angle?
Leya [2.2K]

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65

Step-by-step explanation:

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3 years ago
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir
Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, we find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

\sigma = \sqrt{484} = 22

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

M = z*\frac{\sigma}{\sqrt{n}}

5 = 1.96*\frac{22}{\sqrt{n}}

5\sqrt{n} = 43.12

\sqrt{n} = \frac{43.12}{5}

\sqrt{n} = 8.624

(\sqrt{n})^{2} = (8.624)^{2}

n = 74.4

We need a sample size of at least 75.

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Well 41 divided by 6 is 6.8333333333333 so you just need to subtract .833333333333

I hope this answered your question
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3 years ago
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