Question

F as a function of x is equal to the square root of quantity 6 x plus 9 , f as a function of x is equal to the square root of quantity 6 x minus 9
Find (f + g)(x). (5 points)

Answer 1

Answer:

A. $\sqrt{6x+9} +\sqrt{6x-9}$

Step-by-step explanation:

We are given the functions f(x) and g(x) as,

$f(x)=\sqrt{6x+9}$

$g(x)=\sqrt{6x-9}$

It is required to find the function ( f+g ) i.e. ( f+g ) (x)

So, $(f+g)(x)=f(x)+g(x)$

i.e. $(f+g)(x)=\sqrt{6x+9}+\sqrt{6x-9}$

Hence, we get that $(f+g)(x)=\sqrt{6x+9}+\sqrt{6x-9}$.

So, the first option is correct.