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eduard
3 years ago
14

Part C

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0
Plato answer from edmentum.com

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The answer is A you need to multiply the number of buquets then add it to thr price of the vase
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liraira [26]

Answer:

  • d - cost
  • a - number of attendees

<u>If budget is $99, then the equation is:</u>

  • 99 = a + 96
  • a = 99 - 96
  • a = 3

Maximum number of attendees is 3

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The period of a pendulum is given by the equation
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Step-by-step explanation:

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QUICK ALGEBRA 2 HELP PLEASE. NEEDED ASAP! 3 Q'S!
Goshia [24]
 1.              x -    4
x - 6|x² - 10x + 24
     - (x² -  6x)
               -4x + 24
             - (4x + 24)
                          0
The answer is C.

2. A. 9x² + 12x - 3
        3(x²) + 3(4x) - 3(1)
        3(x² + 4x - 1)

    B. 9x² + 3x - 5
        Not Factored

    C. 6x² + 10x - 4
        2(3x²) + 2(5x) - 2(2)
        2(3x² + 5x - 2)
        2(3x² + 6x - x - 2)
        2(3x(x) + 3x(2) - 1(x) - 1(2))
        2(3x(x + 2) - 1(x + 2))
        2(3x - 1)(x + 2)

    D. 6x² + 7x - 6
         Not Factored

The answer is C.

3.                  3x³ - 4x² + 3x - 6
   x + 2|3x⁴ + 2x³ - 5x² + 0x - 4
         - (3x⁴ + 6x³)
                     -4x³ - 5x²
                  - (-4x³ - 8x²)
                               3x² + 0x
                            - (3x² + 6x)
                                       -6x - 4 
                                    - (-6x - 12)
                                                8
The answer is A.
7 0
3 years ago
(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard
AveGali [126]

Answer:  

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.95=0.05

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: t_{n-1,\alpha/2}=t_{7,0.025}=2.365

Sample mean : \overline{x}=24.8\text{ hours}

Standard deviation : \sigma=3.2\text{ hours}

The confidence interval for population means is given by :-

\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}

24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)

Hence, the 95% confidence interval, assuming the times are normally distributed.=  (22.12, 27.48)

6 0
3 years ago
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