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svetoff [14.1K]
2 years ago
7

What is the value of -3(15-s)+2s^2 when s=-3PLEASE ANSWER QUICKLY!!!!!

Mathematics
1 answer:
harina [27]2 years ago
7 0

Answer:

-36

Step-by-step explanation:

1. Plug -3 into the equation given: -3(15-(-3)+2(-3)^2

2. Use Pemdas and first distribute the negative to negative three then distribute -3 to the rest of the parenthesis (final answer): -45-9 +2(-3)^2

3. Then put -3 to the power of 2 (which is 9) then multiply it by 2 (final answer): -45-9+18

4. Combine all like terms and you get the answer -36!

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An article reported that for a sample of 52 kitchens with gas cooking appliances monitored during a one-week period, the sample
kolbaska11 [484]

Answer:

a) 654.16-2.01\frac{164.55}{\sqrt{52}}=608.29    

654.16+2.01\frac{164.55}{\sqrt{52}}=700.03    

And we can conclude that we are 95% confident that the true mean of Co2 level is between 608.29 and 700.03 ppm

b) n=(\frac{1.960(175)}{25})^2 =188.23 \approx 189

Step-by-step explanation:

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=52-1=51

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,51)".And we see that t_{\alpha/2}=2.01

Replacing we got:

654.16-2.01\frac{164.55}{\sqrt{52}}=608.29    

654.16+2.01\frac{164.55}{\sqrt{52}}=700.03    

And we can conclude that we are 95% confident that the true mean of Co2 level is between 608.29 and 700.03 ppm

Part b

The margin of error is given by :

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

The desired margin of error is ME =50/2=25 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, and we use an estimator of the population variance the value of 175 replacing into formula (b) we got:

n=(\frac{1.960(175)}{25})^2 =188.23 \approx 189

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Answer:

No.

Step-by-step explanation:

The central Limit Theorem states that the sample size must be greater than 30 for an approximate normal distribution.

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Can you help me please I need help with a couple of questions
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Find x please show work if u can​
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Answer:

x is 12

Step-by-step explanation:

You can find x two different ways.

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