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ANTONII [103]
3 years ago
6

An isosceles triangle has its vertex at the origin and its base parallel to the x-axis with the vertices above the axis on the c

urve y = 27-x^2. Find the largest area the triangle can have.
Mathematics
1 answer:
Virty [35]3 years ago
7 0
We are given with an isosceles triangle having a vertex on the curve given y =<span>27-x^2</span> .
The area of the triangle, A= xy = x (27-x^2) 
A' = 27-x^2-2x^2 = 0 
x = 3 
Amax = 3(27-9) = 54 units2
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