Answer:
The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.
Step-by-step explanation:
Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.
The random variable <em>X</em> is exponentially distributed with mean 7 minutes.
Then the parameter of the distribution is,.
The probability density function of <em>X</em> is:
Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:
Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.
Answer:
y=-3/5x+16
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(13-19)/(5-(-5))
m=-6/(5+5)
m=-6/10
simplify
m=-3/5
y-y1=m(x-x1)
y-19=-3/5(x-(-5))
y-19=-3/5(x+5)
y=-3/5x-15/5+19
y=-3/5x-3+19
y=-3/5x+16
The answer is 24 to the 4th power
Answer:
<h2>17</h2>
Step-by-step explanation:
Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)