Answer:
![\°F = 93.2](https://tex.z-dn.net/?f=%5C%C2%B0F%20%3D%2093.2)
City 2 has a higher temperature
Step-by-step explanation:
Given
![\°F = (\°C * 9/5) + 32](https://tex.z-dn.net/?f=%5C%C2%B0F%20%3D%20%28%5C%C2%B0C%20%2A%209%2F5%29%20%2B%2032)
![City\ 2 = 97\°F](https://tex.z-dn.net/?f=City%5C%202%20%3D%2097%5C%C2%B0F)
Required
Convert 34°C to °F
Substitute 34 for C in the above formula:
![\°F = (34 * 9/5) + 32](https://tex.z-dn.net/?f=%5C%C2%B0F%20%3D%20%2834%20%2A%209%2F5%29%20%2B%2032)
![\°F = 61.2 + 32](https://tex.z-dn.net/?f=%5C%C2%B0F%20%3D%2061.2%20%2B%2032)
![\°F = 93.2](https://tex.z-dn.net/?f=%5C%C2%B0F%20%3D%2093.2)
<em>Comparing 93.2 to City 2's temperature of 97; we can conclude that city 2 has a higher temperature</em>
We know that the area is 20.
Since 20 is a small number: lets list out possible combinations of lengths and widths.
1 * 20
2 * 10
4 * 5
L = 7 + 3w
lets see which on makes sense.
L = 7 + 3w
20 = w7 + 3w^2
3w^2 + 7w -20 = 0
(3w - 10)(w - 2)
w can equal 10/3 or 2.
So the dimensions: are Width = 2 Length = 10
14 is always 15 is sometimes 16 is sometimes
Answer:
a) 1.3652
b) 1.3906
Step-by-step explanation:
a) log5 9 = log5 3² = 2log5 3 = 2(0.6826) = 1.3652
b) log5 75/8 = log5 75 - log5 8 = log5 3×25 - log5 8=
log5 3 + log5 5² - log5 8 = 0.6826 + 2 - 1.2920 = 0.6826 + 0.708 = 1.3906